Answer:
reduction in the amount of CO₂ emissions by that household per year is 9517.2 lbm per year
Explanation:
given data
electricity consume = 14000 kWh
fuel consume = 900 gal
CO₂ produced of fuel = 26.4 lbm/gal
CO₂ produced of electricity = 1.54 lbm/kWh
oil and electricity usage = 21 percent
to find out
the reduction in the amount of CO₂ emissions
solution
we calculate the amount of CO₂ produce here that is
amount of CO₂ produce = ( electricity consume×CO₂ produce electricity + fuel consume × CO₂ consume fuel ) ........................1
put here value
amount of CO₂ produce = ( 14000 × 1.54 + 900 × 26.4 )
amount of CO₂ produce = 45320 lbm/yr
we know reduction is 21%
so
reduction in amount of CO₂ produced is
reduction in CO₂ produced = 45320 × 21%
reduction in CO₂ produced = 9517.2 lbm per year
so reduction in the amount of CO₂ emissions by that household per year is 9517.2 lbm per year
V=IR
V=15x11
V=165ohms
I don’t quite remember the unit
Ohms law
To solve this, we simply use trigonometry
the effective value of g along the 45° angle is
g eff = g / sin 45
g eff = g / (√2 / 2)
g eff = 2g / √2
g eff = g √2 ≈ 6.94 m/s²
Answer:
O D.30.0 Ω
Explanation:
this <em>is </em><em>the </em><em>correct </em><em>answer</em><em>!</em>
Answer:
0.39 J/g°c
Explanation:
= heat / unit of mass × unit of temperature
986.75J/16.75g
= 58.9 J/g
∆T=175°c - 25°c = 150°c
986.75 / 150°c = 6.578
986.75 / 16.75g.150°c = 0.30 j/g°c
