Write the equation in POINT-SLOPE FORM of the line that passes throught (5,9) and has a slope of -7.
Answer: 83.5
Step-by-step explanation:
Answer: 6(x²-4x+4-4)+1=0, 6(x-2)²-24+1=0, 6(x-2)²=23, x-2=±√(23/6), x=2±√(23/6)=2±1.95789, so x=3.95789 or 0.04211 approx. these are the zeros.
step by step explanation:
\boxed{\boxed{\dfrac{12+\sqrt{138}}{6},\ \dfrac{12-\sqrt{138}}{6}}}
Solution-
The quadratic function is,
6x^2-24x + 1
a = 6, b = -24, c = 1
x=\dfrac{-b\pm \sqrt{b^2-4ac}}{2a}
=\dfrac{-(-24)\pm \sqrt{-24^2-4\cdot 6\cdot 1}}{2\cdot 6}
=\dfrac{24\pm \sqrt{576-24}}{12}
=\dfrac{24\pm \sqrt{552}}{12}
=\dfrac{24\pm 2\sqrt{138}}{12}
=\dfrac{12\pm \sqrt{138}}{6}
=\dfrac{12+\sqrt{138}}{6},\ \dfrac{12-\sqrt{138}}{6}
Answer:
B. $1430
Step-by-step explanation:
Put 6 in the equation for n and do the arithmetic.
A(6) = 1300 +(6 -1)(0.02·1300)
= 1300(1 +5(.02)) = 1300(1.1)
A(6) = 1430 . . . . matches choice B
0.9 ÷ 4 = 0.225m
I hope this helps, feel free to ask any questions you may have