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3 years ago

12

We want the following inequality to be true: IMAGE BELOW!

1 answer:

marta [7]3 years ago

5 0

Answer:

B. X=7

Step-by-step explanation:

Because 9 greater than 7

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In the order of operations, the absolute value sign is considered to be at which level?

morpeh [17]

Answer:

Note that with embedded parentheses (parentheses within parenthesis), you always perform operations inside out; do the math on the inside before the outside. Note that if you have an absolute value | | sign which means take the positive value only of a number inside.

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1 year ago

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Use the distributive property to rewrite the expression 4(3.5 + 2.3).

Fed [463]

Step-by-step explanation:

4x 3.5 + 4x 2.3

14 + 9.2

= 23.2

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2 years ago

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Q+ad=m solve for d, i need help now please!

Pepsi [2]

Answer:

d =(m-q)/a

Step-by-step explanation:

$q+ad=m\\ad = m-q\\\frac{ad}{a} = \frac{m-q}{a} \\\\d = \frac{m-q}{a}$

7 0

3 years ago

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Y=-x^2+2x+10<br> y=x+2<br><br> Substitution <br> Please show your work<br> Need ASAP

erik [133]

Answer:

The solutions of the system of equations are the points

$(\frac{1-\sqrt{33}} {2},\frac{5-\sqrt{33}} {2})$

$(\frac{1+\sqrt{33}} {2},\frac{5+\sqrt{33}} {2})$

Step-by-step explanation:

we have

$y=-x^{2} +2x+10$ ----> equation A

$y=x+2$ ----> equation B

Solve the system by substitution

substitute equation B in equation A

$x+2=-x^{2} +2x+10$

solve for x

$-x^{2} +2x+10-x-2=0$

$-x^{2} +x+8=0$

The formula to solve a quadratic equation of the form

$ax^{2} +bx+c=0$

is equal to

$x=\frac{-b\pm\sqrt{b^{2}-4ac}} {2a}$

in this problem we have

$-x^{2} +x+8=0$

so

$a=-1\\b=1\\c=8$

substitute in the formula

$x=\frac{-1\pm\sqrt{1^{2}-4(-1)(8)}} {2(-1)}$

$x=\frac{-1\pm\sqrt{33}} {-2}$

$x=\frac{-1+\sqrt{33}} {-2}$ -----> $x=\frac{1-\sqrt{33}} {2}$

$x=\frac{-1-\sqrt{33}} {-2}$ -----> $x=\frac{1+\sqrt{33}} {2}$

<em>Find the values of y</em>

For $x=\frac{1-\sqrt{33}} {2}$

$y=x+2$

$y=\frac{1-\sqrt{33}} {2}+2$ ----> $y=\frac{5-\sqrt{33}} {2}$

For $x=\frac{1+\sqrt{33}} {2}$

$y=x+2$

$y=\frac{1+\sqrt{33}} {2}+2$ ----> $y=\frac{5+\sqrt{33}} {2}$

therefore

The solutions of the system of equations are the points

$(\frac{1-\sqrt{33}} {2},\frac{5-\sqrt{33}} {2})$

$(\frac{1+\sqrt{33}} {2},\frac{5+\sqrt{33}} {2})$

5 0

2 years ago

While mining, Keith found a large metal bar that weighed 42 ounces. Keith was also able to determine that the bar had 30 ounces

Usimov [2.4K]

Divide the silver present in the bar by the total weight of the bar to find the percentage of silver in the bar.

$30 / 42 = 0.7142$

Multiply this decimal by 100 for the percentage.

$.7142 * 100 = 71.42$

Rounded to the nearest tenth, 71.4% of the weight of the bar is silver.

8 0

3 years ago

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