Divide 68 by 85 = is .8 which is 80%
Answer:
108
Step-by-step explanation:
We can rewrite f(x+2) to make it easier to evaluate:
f(x+2) = (6x +5)x -8
Since we want f(6), we want x+2 = 6, or x=4.
f(6) = (6·4 +5)·4 -8 = 29·4 -8
f(6) = 108
Answer:
Isolate the variable by dividing each side by factors that don't contain the variable.
Inequality Form:
p>15
Interval Notation:
(15,∞)
:)
Answer: ![\text{Area of the square shaped traffic sign }=16x^2+9+24x](https://tex.z-dn.net/?f=%5Ctext%7BArea%20of%20the%20square%20shaped%20traffic%20sign%20%7D%3D16x%5E2%2B9%2B24x)
Step-by-step explanation:
Given: The side of the square shaped traffic sign = 4x+3
We know that the area of square is given by:-
![Area= side^2](https://tex.z-dn.net/?f=Area%3D%20side%5E2)
Therefore, the area of the side of the square shaped field is given by:-
![Area=(4x+3)^2](https://tex.z-dn.net/?f=Area%3D%284x%2B3%29%5E2)
We know that , ![(a+b)^2=a^2+b^2+2ab](https://tex.z-dn.net/?f=%28a%2Bb%29%5E2%3Da%5E2%2Bb%5E2%2B2ab)
Therefore,
![(4x+3)^2=(4x)^2+(3)^2+2(4x)(3)\\=16x^2+9+24x](https://tex.z-dn.net/?f=%284x%2B3%29%5E2%3D%284x%29%5E2%2B%283%29%5E2%2B2%284x%29%283%29%5C%5C%3D16x%5E2%2B9%2B24x)
Hence, ![\text{Area of the square shaped traffic sign }=16x^2+9+24x](https://tex.z-dn.net/?f=%5Ctext%7BArea%20of%20the%20square%20shaped%20traffic%20sign%20%7D%3D16x%5E2%2B9%2B24x)