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3 years ago

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1. What are the different offensive and defensive strategies that are used in water polo?

1 answer:

Nezavi [6.7K]3 years ago

8 0

Answer:

A defensive way is use all your might to jump when the ball is coming at you, because as you might know is it takes a lot of effert to jump in a pool, the gravity is very strong in the pool! Or if you get the ball you can throw and swing your arm as strong as you can a HIT that ball! You wanna hit it hard so the players on the other side of the pool don’t get the ball,instead it will go over them and you WIN!

Step-by-step explanation:

Hope this helped :)✨

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The area of a rectangle is 1176 square meters. The width of the rectangle is 21 meters. What i the length of the rectangle?

stepan [7]

Answer:

56

Step-by-step explanation:

1176 divided by 21 = 56

3 0

3 years ago

I need help ASAP PLEASE ASAP!!!

zysi [14]

The area is 10 just use a area calculator!

3 0

2 years ago

Read 2 more answers

4. The West Corporation has a weekly fixed cost of $5000. It costs $40 to produce each

Fantom [35]

Answer: 250 cameras; $10,000 spent; 15,000 made

Step-by-step explanation:

1) FInd the profit. 60-40=20. This means that they make a profit of $20 per camera.

2) How many cameras to break even? 5000/20=250. The answer is 250 cameras!

3) How much money has been spent? 40x250= $10000 spent.

4) How much money has been made? 60x250= $15000 made.

<em>Hope this helps!</em>

6 0

2 years ago

Please helppppppppp.....

Lana71 [14]

Answer: B

Step-by-step explanation:

7 0

3 years ago

Solve using the quadratic formula 3x^2+11x+5=0

storchak [24]

Answer:

$3x^2 + 11x + 5 = 0 : x = \frac{-11 + \sqrt{61} }{6} , x = \frac{-11 - \sqrt{61} }{6}$

Decimal:

$(x = -0.53162..., x = -3.13504...)$

Step-by-step explanation:

$3x^2+11x+5=0$

Solve with the quadratic formula:

For a quadratic equation of the form $ax^2+bx+c=0$ the solutions are:

$x_{1,\:2}=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

For $a=3,\:b=11,\:c=5:\quad x_{1,\:2}=\frac{-11\pm \sqrt{11^2-4\cdot \:3\cdot \:5}}{2\cdot \:3}$

$x=\frac{-11 + \sqrt{11^2-4\cdot \:3\cdot \:5}}{2\cdot \:3} : \frac{-11 + \sqrt{61} }{6}$

$x=\frac{-11 - \sqrt{11^2-4\cdot \:3\cdot \:5}}{2\cdot \:3} : \frac{-11 - \sqrt{61} }{6}$

The solutions to the quadratic equation are:

$x=\frac{-11+\sqrt{61}}{6},\:x=\frac{-11-\sqrt{61}}{6}$

Hope I helped. If so, may I get brainliest and a thanks?

Thank you, have a good day! =)

8 0

3 years ago