Find the solution of the initial value problem 2y−3y+y=0
1 answer:
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Remember
(x^m)/(x^n)=x^(m-n)
(q^(33/4))/(q^8)=q^((33/4)-8)
what is 33/4-8?
33/4-8=33/4-32/4=1/4
result is
q^1/4 or![\sqrt[4]{q}](https://tex.z-dn.net/?f=%20%5Csqrt%5B4%5D%7Bq%7D%20)
answer is
(x^m)/(x^n)=x^(m-n)
(q^(33/4))/(q^8)=q^((33/4)-8)
what is 33/4-8?
33/4-8=33/4-32/4=1/4
result is
q^1/4 or
answer is