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vaieri [72.5K]
3 years ago
14

The table shows a linear function. Which equation represents the function?

Mathematics
1 answer:
marin [14]3 years ago
8 0
You have a great day and you can
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I need to know Simplify 2a + 8(b + a) is
KonstantinChe [14]
HELLO !

Okay so what you do is<em> eliminate the parenthesis </em>in the equation because it really helps

So you would multiply 8 and b
Also multiple 8 and a

You would get 8b and 8a

Your equation would look like ...

2a + 8b + 8a = ...

<em>Now you add the alike things in the equation </em>

8a and 2a are the alike things.

Now you would have ...

10a + 8b = ?






4 0
4 years ago
Find the distance between the points (4, 3) and (0, 6).
Ilia_Sergeevich [38]

Answer:

5

Step-by-step explanation:

√(x2 - x1)² + (y2 - y1)²

√(0 - 4)² + (6 - 3)²

√(-4)² + (3)²

√(16) + (9)

√25

= 5

8 0
3 years ago
Part of the proceeds from a garage sale was $455 worth of $5 bills and $20 bills. If there were 6 more $5 bills than 20$ bills f
Feliz [49]

Answer:

\large \boxed{\text{17 \$20 bills and 23 \$5 bills}}

Step-by-step explanation:

               Let x = the number of $20 bills.

     Then x + 6 = the number of $5 bills  and

20x + 5(x +  6) = 455

\begin{array}{rcl}20x + 5(x + 6) & = & 455\\20x + 5x + 30 & = & 455\\25x + 30 & = & 455\\25x & = & 425\\x & = &\dfrac{425}{25}\\\\x & = &\mathbf{17}\\\end{array}

                    x = 17 = number of $20 bills

x + 6 = 17 + 6 = 23 = number of $5 bills

\text{There were }\large \boxed{\textbf{17 \$20 bills and 23 \$5 bills}}

Check:

\begin{array}{rcl}20\times17+ 5(17 + 6) & = & 455\\340 + 5\times23& = & 455\\340 + 115 & = & 455\\455 & = & 455\\\end{array}

OK.

7 0
3 years ago
PLEASE HELP HOMEWORK DUE IN 5 MINUTES
VARVARA [1.3K]

Answer:

????

Step-by-step explanation:

what is the question

4 0
4 years ago
Read 2 more answers
Solve the decay equation y' = -ky using the integrating factors method. Show work
Alex777 [14]

Answer:

y=\frac{c}{e^{kx}}

Step-by-step explanation:

\frac{\mathrm{d} y}{\mathrm{d} x} =-ky

\frac{\mathrm{d} y}{\mathrm{d} x} +ky=0

comparing with equation

\frac{\mathrm{d} y}{\mathrm{d} x} + Py=Q(x)

I.F.= e^{\int P dx}

I.F.= e^{\int k dx}

I.F.= e^{kx}

y=\frac{1}{I.F.} ( \int {Q(x)}  dx  +c)

y=\frac{1}{e^{kx}} ( \int {0}  dx  +c)

y=\frac{c}{e^{kx}}

7 0
4 years ago
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