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Andre45 [30]
3 years ago
7

What causes heartburn? How do antacids work to relieve heartburn? What are the key

Chemistry
1 answer:
Sophie [7]3 years ago
7 0

Answer:

<h3>Antacids use a combination of calcium, magnesium, and aluminum salts as their active ingredients. These medications work by neutralizing the acid in the stomach. They also inhibit pepsin , which is an enzyme that plays a role in protein digestion.</h3>

Hope this answer helps

Mark me as brainlest

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Jake collected samples of two substances while he was out walking. After taking the samples home, he ran tests and found that on
inysia [295]

The answer is: first substance is base and second is acid.

Bases, for example solution of sodium hydroxide (NaOH) feels slipery.

Sodium hydroxide dissociation in water: NaOH(aq) → Na⁺(aq) + OH⁻(aq).

Ionic compounds are good good electricity and heat conductors, because ionic compounds have mobile ions (cations and anions) that are able to transfer electrical charge.

In second reaction, magnesium is oxidized from oxidation number 0 to +2 and  hydrogen is reduced from +1 to 0 (hydrogen gas).

7 0
4 years ago
Read 2 more answers
Which of the following are physical properties of a penny? Choose all that are correct.
malfutka [58]
Slightly red in color is the only physical property
6 0
3 years ago
Methanol (CH3OH) is produced commercially by the catalyzed reaction of carbon monoxide and hydrogen:
Effectus [21]

Answer: Kc= 4.653

Explanation:

From The equation of reaction

CO(g)+2H2(g)⇌CH3OH(g)

From the question

[CH3OH] =0.0679 moles

[CO]= 0.160moles

[H2]= 0.302

Kc = [CH3OH]/[CO] [H2]^2

Kc=[0.069]/[0.16]×[0.302]^2

Kc= 4.653

5 0
3 years ago
What is the frequency of light with an energy of 124 kJ/mol?
Charra [1.4K]

Answer: = 3.11 x 10^14 s^-1

Explanation:

Use the formula E = hv

This formula uses the assumption that the unit for energy is in Joules/photon.

124 kJ = 124000J

To get 124000J/mol into a unit of J/photons, we need to divide by the number of photons in a mole, which is 6.022 x 10^23.

And thus, we need

124000/6.022 x 10^23 = 2.06 x 10^-19J/photon

We can plug it in to E = hv by

2.06 x 10^-19J = (6.63 x 10^-34 J s)(v) Isolate v by

v = (2.06 x 10^-19J)/(6.63 x 10^-34 J s)

= 3.11 x 10^14 s^-1

6 0
3 years ago
The naturally occurring isotopes of vanadium are vanadium-50 and vanadium-51. Vanadium-50 has an abundance of 0.250% and a mass
fomenos

Answer:

The answer to your question is letter A

Explanation:

                            Abundance              Atomic mass

       V-50             0.25%                         49.947

       V-51            99.750%                       50.944

Formula

Average atomic mass = [V-50-Abundance x V-50-Atomic mass] +

                                       [ V-51-Abundance x V-51-Atomic mass]

Substitution

Average atomic mass = [ 0.0025 x 49.947] + [0.9975 x 50.944]

                                    = 0.125 + 50.817

Result

                                    = 50.942 amu

4 0
3 years ago
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