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4 years ago

Identifying Physical Properties of Matter

Chemistry

2 answers:

Vedmedyk [2.9K]4 years ago

4 0

Answer:

The formation of sand is a physical change because some of the physical properties of the rocks change, but their identities do not. The particles of rock are rearranged as their sizes and shapes change, but their identities and total mass remain the same.

Explanation:

sample response on edge2020

kap26 [50]4 years ago

3 0

Answer:

plzz mark brainliast

Explanation:

because there is no chemical change in the situation. there is only change in its state.

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Why does the pink color, which forms at the point where NaOH comes into contact with the solution (HCl) in the flask, disappear

Novay_Z [31]

Answer is: because pH value of solution is changing.
Balanced chemical reaction: NaOH(aq) + HCl(aq) → NaCl(aq) + H₂O(l).
pH of sodium hydroxide solution is above seven (basic), when solution of hydrochloric acid is added, pH slowly dropping until it became neutral solution (pH is equal seven) and that is endpoint of titration.

4 0

3 years ago

What produced the sulfuric acid that helped form the Lechugilla caves

Mila [183]

The answer you need is B. Pollution. Have in mind that Caves contain carvings and depictions that are formed from acids running through the limestones of the cave. The sulfuric acid that helped form the Lechugilla caves come from pollution.I hope this info can help you

7 0

3 years ago

How many grams of NaCl are contained in 0.50 L of a 1.20 M solution?

kenny6666 [7]

Answer:

35.06 g NaCl

Explanation:

mol = 0.5 L * 1.2 M

Na mass = 22.99 g

Cl mass = 35.45 g

0.6 mol * (22.99 g + 35.45 g)/1 mol = 35.06 g NaCl

7 0

3 years ago

How many liters of

Kruka [31]

The balanced equation for the above reaction is as follows
C₆H₁₂O₆(s) + 6O₂(g) --> 6H₂O(g) + 6CO₂<span>(g)
the limiting reactant in the equation is glucose as the whole amount of glucose is used up in the reaction.
the amount of </span>C₆H₁₂O₆ used up - 13.2 g
the number of moles reacted - 13.2 g/ 180 g/mol = 0.073 mol
stoichiometry of glucose to CO₂ - 1:6
then number of CO₂ moles are - 0.073 mol x 6 = 0.44 mol
As mentioned this reaction takes place at standard temperature and pressure conditions,
At STP 1 mol of any gas occupies 22.4 L
Therefore 0.44 mol of CO₂ occupies 22.4 L/mol x 0.44 mol = 9.8 rounded off - 10.0 L
Answer is B) 10.0 L CO₂

3 0

4 years ago

For the following reaction, 42.2 grams of potassium hydrogen sulfate are allowed to react with 21.4 grams of potassium hydroxide

ASHA 777 [7]

Answer:

53.99g

Explanation:

Step 1:

The balanced equation for the reaction. This is given below:

KHSO4(aq) + KOH(aq) —> K2SO4(aq) + H2O(l)

Step 2:

Determination of the masses of KHSO4 and KOH that reacted and the mass of K2SO4 produced from the balanced equation.

This is illustrated below:

Molar mass of KHSO4 = 39 + 1 + 32 + (16x4) = 136g/mol

Mass of KHSO4 from the balanced equation = 1 x 136 = 136g

Molar mass of KOH = 39 + 16 + 1 = 56g/mol

Mass of KOH from the balanced equation = 1 x 56 = 56g

Molar mass of K2SO4 = (39x2) + 32 + (16x4) = 174g/mol

Mass of K2SO4 from the balanced equation = 1 x 174 = 174g.

From the balanced equation above, 136g of KHSO4 reacted with 56g of KOH to produce 174g of K2SO4

Step 3:

Determination of the limiting reactant. This is illustrated below:

From the balanced equation above, 136g of KHSO4 reacted with 56g of KOH.

Therefore, 42.2g of KHSO4 will react with = (42.2 x 56)/136 = 17.38g of KOH.

From the above calculations, we can see that only 17.38g out of 21.4g of KOH given was needed to react completely with 42.2g of KHSO4.

Therefore, KHSO4 is the limiting reactant and KOH is the excess reactant.

Step 4:

Determination of the maximum mass of K2SO4 produced from the reaction.

In this case, the limiting reactant will be used as all of it is used up in the reaction. The limiting reactant is KHSO4 and the maximum amount of K2SO4 produced can be obtained as follow:

From the balanced equation above, 136g of KHSO4 reacted to produce 174g of K2SO4.

Therefore, 42.2g of KHSO4 will react to produce = (42.2 x 174)/136 = 53.99g of K2SO4.

Therefore, the maximum amount of K2SO4 produced is 53.99g.

8 0

3 years ago