An Arrhenius base is a compound that increases the OH − ion concentration in aqueous solution. The reaction between an Arrhenius acid and an Arrhenius base is called neutralization and results in the formation of water and a salt.
LiAlH₄ is used as strong reducing agent. The hydride produced acts as a nucleophile and attacks the electrophillic carbon of carbonyl group. In given example two reactions are observed.
Reaction 1: In first step LiAlH₄ when treated with
Ester produces corresponding
Aldehyde and alcohol.
Reaction 2: This aldehyde produced further reacts with LiAlH₄ to give a reduced product (
Alcohols). In this case Butanol is produced.
The reaction schemes are shown as felow,
Molar solubility is number of moles of the solute that can be dissolved per liter of solution before the solution becomes saturated.
The molar solubility of lead(ii) chloride with ksp value of 2.4 × 10e4 can be solve as:
Ksp = s2 = 2.4 × 10e4
s2 = 2.4 × 10e4
s = √(2.4 × 10e4)
s = 154.9 mol/L
Answer: polar protic solvents solvate the nucleophile necessary for attack on the substrate in SN2 substitution.
Explanation:
Aprotic solvents are solvents that lack protons such as dimethyl sulphoxide (DMSO). DMSO has no exposed positive end. The positive end is buried inside the molecular structure. As a result of this, the nucleophile is not solvated. If the nucleophile is solvated, the rate of SN2 reaction will reduce drastically because the nucleophile becomes unavailable to attack the substrate. This solvation normally occur in polar protic solvents such as water because of the exposed positive end of the molecule which interacts with the nucleophile thereby reducing the rate of SN2 reaction.
Given :
Number of atoms of an element, n = 2.072 × 10⁴³ atoms.
To Find :
Number of moles of that element in given number of atoms.
Solution :
We know, 1 mole of any element contains 6.022 × 10²³ atoms.
So, number of moles in given number of atoms are :

Hence, this is the required solution.