Ok! So, given a quadratic function<span>, </span>y<span> = ax</span>2<span> + bx + c, when "a" is positive, the </span>parabola <span>opens upward and the vertex is the minimum value. On the other hand, if "a" is negative, the graph opens downward and the vertex is the maximum value. Now, let's refer back to our original graph, </span>y<span> = </span><span>x2</span><span>, where "a" is 1.
Hope this helps.</span>
Answer:

Step-by-step explanation:
We want to find the equation of a circle with a center at (7, 2) and a point on the circle at (2, 5).
First, recall that the equation of a circle is given by:

Where (<em>h, k</em>) is the center and <em>r</em> is the radius.
Since our center is at (7, 2), <em>h</em> = 7 and <em>k</em> = 2. Substitute:

Next, the since a point on the circle is (2, 5), <em>y</em> = 5 when <em>x</em> = 2. Substitute:

Solve for <em>r: </em>
<em />
<em />
Simplify. Thus:

Finally, add:

We don't need to take the square root of both sides, as we will have the square it again anyways.
Therefore, our equation is:

Answer:
y= (x+1)(x+ .5) (x+ 3.5)
y= (x+1) (X - .5) (x-3.5)
y = (x-1) (X-.5) (x-3.5)
y= (x+1) (X- .5) (x +3.5)
Step-by-step explanation:
The standard form of this equation is

The slope of two parallel lines i the same, so the slope of the line we're looking for is also

Since the line passes through

, the equation is:
