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pashok25 [27]
3 years ago
7

Do girls read more than boys during the summer? Serena's class asked

Mathematics
1 answer:
Veseljchak [2.6K]3 years ago
7 0

Answer:

Step-by-step explanation:

I dont know how to do the box thing, but I added all the things and boys read more.

girls:1870

boys:1952

The diffrence (when subracting) is 82

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What’s the answer did anyone figure it out ?
olya-2409 [2.1K]

Answer:

NAswer to what

Step-by-step explanation:

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X and Y coordinates which Way is ask and which Way is why is why upper down or is X upper down is why upper down or is X up or d
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X is side to side and Y is up and down. Hope this helps.
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4 years ago
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Independent and dependent events
trapecia [35]
Definitions
Independent events= one outcome of an event doesn’t affect the other outcomes
Dependent events= one outcome of an event affects the other outcomes

Examples
Independent= Jack has a standard deck of cards 52 cards( 26 red and 26 black) what is the probability that he picks a red card or a spade?

Dependent= Jack has a standard deck of cards. What is the probability that he picks a red card or a diamond?
7 0
4 years ago
Find the inverse matrix or type "none". (use decimals) {11 -5 3 -1}
alexira [117]

The inverse of the matrix  \left[\begin{array}{cc}11&-5\\3&-1\end{array}\right] is the matrix \left[\begin{array}{cc}\frac{-1}{4} &\frac{5}{4} \\\\\frac{-3}{4} &\frac{11}{4} \end{array}\right] .

The inverse of a matrix A is calculated by the formula:

A' = (1/|A|)(Adj A),

where A' represents the inverse of matrix A,

|A| represents the determinant value of matrix A, and

Adj A represents the Adjoin matrix of matrix A.

So, to calculate the inverse of the matrix  \left[\begin{array}{cc}11&-5\\3&-1\end{array}\right] , we will first calculate its Adj.

Adj = \left[\begin{array}{cc}-1&-3\\5&11\end{array}\right] ^{T}= \left[\begin{array}{cc}-1&5\\-3&11\end{array}\right].

Now, we calculate |A| = 11*(-1) - (-5)*3 = -11 + 15 = 4.

Therefore A' = (1/|A|)(Adj A),

or, A' = (1/4)*\left[\begin{array}{cc}-1&5\\-3&11\end{array}\right] ,

or, A' = \left[\begin{array}{cc}\frac{-1}{4} &\frac{5}{4} \\\\\frac{-3}{4} &\frac{11}{4} \end{array}\right] .

Therefore, the inverse of the matrix  \left[\begin{array}{cc}11&-5\\3&-1\end{array}\right] is the matrix \left[\begin{array}{cc}\frac{-1}{4} &\frac{5}{4} \\\\\frac{-3}{4} &\frac{11}{4} \end{array}\right] .

Learn more about the inverse of a matrix at

brainly.com/question/16862241

#SPJ10

4 0
2 years ago
Please help with the questions in the image
Pavel [41]

Answer:   f(x) = (x - 3)²

<u>Step-by-step explanation:</u>

Use the vertex formula: y = a(x - h)² + k

and input the vertex (h, k) = (3, 0) and the given point (x, y) = (4, 2) to solve for a

2 = a(4 - 3)² + 0

2 = a(1)²

2 = a

Now, input (h, k) = (3, 0) and a = 1 into the vertex formula:

y = 1(x - 3)² + 0    →     y = (x - 3)²  

****************************************************************************

Answer:   g(x) = -(x + 1.25)² + 2.5625

<u>Step-by-step explanation:</u>

Use the vertex formula: y = a(x - h)² + k

and input the given points for (x, y) to create a system of equations, then solve for a, h, and k.

EQ1: 2 = a(-2 - h)² + k  

       2 = a(4 + 4h + h²) + k

       2 - 4a - 4ah - ah² = k


EQ2: 1 = a(0 - h)² + k

        1 = ah² + k

        1 - ah² = k


EQ3: -2.5 = a(1 - h)² + k

        -2.5 = a(1 - 2h + h²) + k

        -2.5 -a + 2h + ah² = k

<u>Substitute</u> - set EQ1 = EQ2 and EQ2 = EQ3 to eliminate k

EQ1 = EQ2:     2 - 4a - 4ah - ah² = 1 - ah²

                                 1 - 4a - 4ah = 0    

EQ2 = EQ3:     1 - ah² = -2.5 - a + 2ah - ah²

                                3.5 + a - 2ah = 0  

<u>Elimination:</u>  - now solve the system for "a"

 1 - 4a - 4ah = 0    →    1(1 - 4a - 4ah = 0)    →     1 - 4a - 4ah = 0

3.5 + a - 2ah = 0   →   -2(3.5 + a - 2ah = 0) →  <u> -7 - 2a + 4ah = 0 </u>

                                                                         -6 - 6a           = 0

                                                                              -6a            = 6

<h2>                                                     a     = -1</h2>

Next, replace "a" with -1 into either of the equations to solve for "h"

                                         1 - 4a - 4ah = 0

                                     1 - 4(-1) - 4(-1)h = 0

                                            1 + 4 + 4h = 0

                                                 5 + 4h = 0

                                                       4h = -5

<h2>                                     h = -1.25</h2>

Now, replace "a" with -1 and "h" with -1.25 into any of the original equations (EQ1, EQ2, or EQ3) to solve for k:

1 - ah² = k

1 - (-1)(-1.25)² = k

1 - (-1)(1.5625) = k

1 + 1.5625 = k

<h2> 2.5625 = k</h2>

Now, input (h, k) = (-1.25, 2.5625) and a = -1 into the vertex formula:

y = -1(x - (-1.25))² + 2.5625    →     y = -(x + 1.25)² + 2.5625

4 0
4 years ago
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