3 years ago

Can anyone help me in this question?

Physics

1 answer:

Anna71 [15]3 years ago

3 0

Answer:

I guess the answer is charging by friction

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$tan\theta' = \frac{y}{3}$

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$\frac{dtan\theta'}{dt} = \frac{dy}{3dt}$

Applying chain rule:

$\frac{dtan\theta'}{d\theta'}.\frac{d\theta'}{dt} = \frac{dy}{3dt}$

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