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insens350 [35]
2 years ago
5

Match each term to the best description

Physics
1 answer:
Ronch [10]2 years ago
5 0

Answer:

Coefficient of friction =  Magnitude depends on the interacting materials

Friction = A force that acts parallel to the surface.

kinetic friction = A force that is constant regardless of the applied force

Normal = A force that acts perpendicular to the surface

Static friction = A force that increases as applied force increases up to some maximum value

Explanation:

Let's define all the forces, and then let's solve the problem.

Normal force:

When an object rests on some place (like a book on the table) the force that causes the book to not fall through the table is called the normal force, which is usually equal to the weight of the object and acts perpendicular to the surface where the object is resting.

Friction force.

When an object moves (or tries to move) parallel to a surface, such that the object is in contact with that surface, there appears a force that opposes to the movement (the force is parallel to the surface, and in the opposite direction to the movement).

And this force can be written as:

F = -N*μ

Where μ is the coefficient of friction and N is the normal force.

If the object is not moving yet (but there is applied a force that would move the object) the coefficient is called the coefficient of static friction which increases in a given range, until it can't keep increasing and the object starts to move, while if the object is moving, the coefficient is called the coefficient of kinetic friction and it is constant, where usually the first one is larger than the second, and these coefficients depend on both materials, the surface one and the object one.

Then we have two friction forces, one called the kinetic friction and the other called the static friction.

Then:

Coefficient of friction =  Magnitude depends on the interacting materials

Friction = A force that acts parallel to the surface.

kinetic friction = A force that is constant regardless of the applied force

Normal = A force that acts perpendicular to the surface

Static friction = A force that increases as applied force increases up to some maximum value

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I wish to use a step up transformer to turn an initial RMS AC voltage of 100 V into a final RMS AC voltage of 200 V. What is the
zhuklara [117]

Answer:

1:2

Explanation:

It is given that,

Initial RMS AC voltage is 100 V and final RMS AC voltage is 200 V.

We need to find the ratio of the number of turns in the primary to the secondary  for step up transformer.

For a transformer, \dfrac{V_1}{V_2}=\dfrac{N_1}{N_2}

So,

\dfrac{N_1}{N_2}=\dfrac{100}{200}\\\\\dfrac{N_1}{N_2}=\dfrac{1}{2}

So, the ratio of the number of turns in the primary to the secondary is 1:2.

4 0
3 years ago
A long, current-carrying solenoid with an air core has 1800 turns per meter of length and a radius of 0.0165 m. A coil of 210 tu
Hoochie [10]

Answer:

The mutual inductance is  M  =  0.000406 \  H

Explanation:

From the question we  are told that

    The  number of turns per unit length  is  N =  1800

    The radius is  r = 0.0165 \ m

     The  number of turns of the solenoid is  N_s  =  210 \ turns

   

Generally the mutual inductance of the  system is mathematically represented as

       M  =  \mu_o  *  N *  N_s  *  A

Where A is the cross-sectional area of the system which is mathematically represented as

       A  =  \pi  *  r^2

substituting values

      A  =  3.142 *  (0.0165)^2

       A  =  0.0008554 \ m^2

also   \mu_o is the permeability of free space with the value  \mu_o  =   4\pi * 10^{-7} N/A^2

So  

      M  =  4\pi * 10^{-7}   *1800 *  210  *  0.0008554

      M  =  0.000406 \  H

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3 years ago
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3 years ago
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18°C = _____ <br>-255 K<br> 0 K <br>18 K <br>291 K
Nadya [2.5K]

18°C answer is 291 k

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3 years ago
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Suppose the space shuttle is in orbit 300 km from the Earth's surface, and circles the earth about once every 90
Valentin [98]

The centripetal acceleration of the space shuttle is 9.0 m/s^2 (0.9g)

Explanation:

The period of revolution of the space shuttle is

T=90 min \cdot 60 = 5400 s

From the period, we can calculate the angular speed of the space shuttle, which is given by

\omega = \frac{2\pi}{T}=\frac{2\pi}{5400}=1.16\cdot 10^{-3} rad/s

Now we can calculate the centripetal acceleration of the space shuttle, given by

a=\omega^2 r

where

\omega=1.16\cdot 10^{-3} rad/s is the angular speed

r=6.40 \cdot 10^6 m +300\cdot 10^3 m = 6.7\cdot 10^3 m is the distance of the shuttle from the Earth's centre (it is the  sum of the Earth's radius, 6400 km, and of the altitude of the space shuttle, 300 km)

Substituting and solving, we find

a=(1.16\cdot 10^{-3})^2(6.7\cdot 10^6)=9.0 m/s^2

And since g=9.8 m/s^2, this can be rewritten as

a=\frac{9.0}{9.8}=0.9g

Learn more about centripetal acceleration:

brainly.com/question/2562955

#LearnwithBrainly

7 0
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