Answer:
Case 1:
![AB = 30](https://tex.z-dn.net/?f=AB%20%3D%2030)
![BC = 50](https://tex.z-dn.net/?f=BC%20%3D%2050)
Case 2:
![AB = 15.9](https://tex.z-dn.net/?f=AB%20%3D%2015.9)
![BC = 36.7](https://tex.z-dn.net/?f=BC%20%3D%2036.7)
Case 3: Not possible
Step-by-step explanation:
Given
See attachment for illustration of each case
Required
Find AB and BC
Case 1:
Using Pythagoras theorem in ANB, we have:
![AB^2 = AN^2 + BN^2](https://tex.z-dn.net/?f=AB%5E2%20%3D%20AN%5E2%20%2B%20BN%5E2)
This gives:
![AB^2 = 24^2 + 18^2](https://tex.z-dn.net/?f=AB%5E2%20%3D%2024%5E2%20%2B%2018%5E2)
![AB^2 = 576 + 324](https://tex.z-dn.net/?f=AB%5E2%20%3D%20576%20%2B%20324)
![AB^2 = 900](https://tex.z-dn.net/?f=AB%5E2%20%3D%20900)
Take square roots of both sides
![AB = \sqrt{900](https://tex.z-dn.net/?f=AB%20%3D%20%5Csqrt%7B900)
![AB = 30](https://tex.z-dn.net/?f=AB%20%3D%2030)
To calculate BC, we consider ANC, where:
![AC^2 = AN^2 + NC^2](https://tex.z-dn.net/?f=AC%5E2%20%3D%20AN%5E2%20%2B%20NC%5E2)
![40^2 = 24^2 + NC^2](https://tex.z-dn.net/?f=40%5E2%20%3D%2024%5E2%20%2B%20NC%5E2)
![1600 = 576 + NC^2](https://tex.z-dn.net/?f=1600%20%3D%20576%20%2B%20NC%5E2)
Collect like terms
![NC^2 = 1600 - 576](https://tex.z-dn.net/?f=NC%5E2%20%3D%201600%20-%20576)
![NC^2 = 1024](https://tex.z-dn.net/?f=NC%5E2%20%3D%201024)
Take square roots
![NC = \sqrt{1024](https://tex.z-dn.net/?f=NC%20%3D%20%5Csqrt%7B1024)
![NC = 32](https://tex.z-dn.net/?f=NC%20%3D%2032)
So:
![BC = NC + BN](https://tex.z-dn.net/?f=BC%20%3D%20NC%20%2B%20BN)
![BC = 32 + 18](https://tex.z-dn.net/?f=BC%20%3D%2032%20%2B%2018)
![BC = 50](https://tex.z-dn.net/?f=BC%20%3D%2050)
Case 2:
Using Pythagoras theorem in ANB, we have:
![AN^2 = AB^2 + BN^2](https://tex.z-dn.net/?f=AN%5E2%20%3D%20AB%5E2%20%2B%20BN%5E2)
This gives:
![24^2 = AB^2 + 18^2](https://tex.z-dn.net/?f=24%5E2%20%3D%20AB%5E2%20%2B%2018%5E2)
![576 = AB^2 + 324](https://tex.z-dn.net/?f=576%20%3D%20AB%5E2%20%2B%20324)
Collect like terms
![AB^2 = 576 - 324](https://tex.z-dn.net/?f=AB%5E2%20%3D%20576%20-%20324)
![AB^2 = 252](https://tex.z-dn.net/?f=AB%5E2%20%3D%20252)
Take square roots of both sides
![AB = \sqrt{252](https://tex.z-dn.net/?f=AB%20%3D%20%5Csqrt%7B252)
![AB = 15.9](https://tex.z-dn.net/?f=AB%20%3D%2015.9)
To calculate BC, we consider ABC, where:
![AC^2 = AB^2 + BC^2](https://tex.z-dn.net/?f=AC%5E2%20%3D%20AB%5E2%20%2B%20BC%5E2)
![40^2 = 252 + BC^2](https://tex.z-dn.net/?f=40%5E2%20%3D%20252%20%2B%20BC%5E2)
![1600 = 252 + BC^2](https://tex.z-dn.net/?f=1600%20%3D%20252%20%2B%20BC%5E2)
Collect like terms
![BC^2 = 1600 - 252](https://tex.z-dn.net/?f=BC%5E2%20%3D%201600%20-%20252)
![BC^2 = 1348](https://tex.z-dn.net/?f=BC%5E2%20%3D%201348)
Take square roots
![BC = \sqrt{1348](https://tex.z-dn.net/?f=BC%20%3D%20%5Csqrt%7B1348)
![BC = 36.7](https://tex.z-dn.net/?f=BC%20%3D%2036.7)
Case 3:
This is not possible because in ANC
The hypotenuse AN (24) is less than AC (40)
X/-7 -2 =10
x/-7 = 12
x = -84
Answer:
Yes! Our total savings on gas proportional to the number of beverages you purchase.
Step-by-step explanation:
Here, each liter of gas costs $3.
Every beverage you purchase you save $0.20.
So, if you purchase for $9, you will save 3*$0.20 = $0.60
So, this is proportional because when increase in purchase, there is proportional increase in savings.
Answer:
Rate of change of the diameter is equal to 0.053cm/min
Step-by-step explanation:
A snowball is of the shape of a sphere
Surface area of Sphere (S)= ![4*pi*R^2](https://tex.z-dn.net/?f=4%2Api%2AR%5E2)
Rate of change of surface area
dS/dt = -4![cm^2/min](https://tex.z-dn.net/?f=cm%5E2%2Fmin)
the negative sign indicates the surface area is decreasing.
Radius = d/2 where d represents diameter
using this is the surface area equation
S = ![4*pi*(d/2)^2](https://tex.z-dn.net/?f=4%2Api%2A%28d%2F2%29%5E2)
= ![pi*d^2](https://tex.z-dn.net/?f=pi%2Ad%5E2)
dS/dt = 2*pi*d*d(d)/dt
4 = 2*pi*d*(d)/dt
d(d)/dt = 2/12*pi=
cm/min
so the rate of change of the diameter is equal to 0.053cm/min
He needs 3 1/4 more yards of fabric because 5.5 - 2.25 = 3.25