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3 years ago

50 POINTS!!!!!!!

Physics

1 answer:

miv72 [106K]3 years ago

3 0

Answer:

A. The shorter the distance the greater the force, so now the force would have increased because they haven't moved away from each other.

B. The force would decrease because they are now further apart.

C. the force wouldn't be as great as before but the force would still be high because they are not far apart from each other.

I hope this helps you( ◜‿◝ )♡

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An object 16.8 cm tall is placed in front of a converging lens. A real image, 46 cm tall, is formed on the other side of the len

worty [1.4K]

Answer:

2.74

Explanation:

Magnification = image distance/object distance

Mag = v/u

Given

v = 46cm

u = 16.8

Magnification = 46/16.8

Magnification = 2.74

Hence the magnification is 2.74

7 0

3 years ago

Benjamin recently issued new mobile phones to the marketing team at his company. Each phone can transmit encrypted information f

Misha Larkins [42]

Complete Question:

Which technology is set up on the marketing team's phones?

a) Bluetooth

b) Tethering

c) NFC

d) Hotspot

Answer:

NFC

Explanation:

Near Field Communication (NFC) is a short-range wireless connectivity standard that uses magnetic field induction to enable communication between devices when brought within a few centimetres from each other. NFC offers a secured communication between connected electronic devices with simple setup that can be used to bootstrap more-capable wireless connections. It only covers a range of 10 cm to 20 cm.

None of the other options can transmit or share information for payments among the team except the NFC. NFC is also suitable for this setup because only a small range is expected to be covered.

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3 years ago

Compute the longitudinal strength of an aligned carbon fiber-epoxy matrix composite having a 0.25 volume fraction of fibers, ass

zmey [24]

Answer:

632.5 MPa

Explanation:

$\sigma_{m}$ = Matrix stress at fiber failure = 10 MPa

$V_f$ = Volume fraction of fiber = 0.25

$\sigma_f$ = Fiber fracture strength = 2.5 GPa

The longitudinal strength of a composite is given by

$\sigma_{cl}=\sigma_{m}(1-V_f)+\sigma_fV_f\\\Rightarrow \sigma_{cl}=10(1-0.25)+(2.5\times 10^3)\times 0.25\\\Rightarrow \sigma_{cl}=632.5\ MPa$

The longitudinal strength of the aligned carbon fiber-epoxy matrix composite is 632.5 MPa

8 0

3 years ago

What average force is required to stop an 1100-kg car in 8.0s if the car is travelling at 95km/h?

Semenov [28]

Answer: 13062.5 N

What average force is required to stop an 1100-kg car in 8.0 s if it is traveling at 95 km/h? i got the answer to be 13062.

6 0

3 years ago

A certain fuse "blows" if the current in it exceeds 1.0 A, at which instant the fuse melts with a current density of What is the

Alborosie

Answer:

Explanation:

The complete question is

a certain fuse "blows" if the current in it exceeds 1.0 A, at which instant the fuse melts with a current density of 620 A/ cm^2. What is the diameter of the wire in the fuse?

A) 0.45 mm

B) 0.63 mm

C.) 0.68 mm

D) 0.91 mm

Current in the fuse is 1.0 A

Current density of the fuse when it melts is 620 A/cm^2

Area of the wire in the fuse = I/ρ

Where I is the current through the fuse

ρ is the current density of the fuse

Area = 1/620 = 1.613 x 10^-3 cm^2

We know that 10000 cm^2 = 1 m^2, therefore,

1.613 x 10^-3 cm^2 = 1.613 x 10^-7 m^2

Recall that this area of this wire is gotten as

A = $\frac{\pi d^{2} }{4}$

where d is the diameter of the wire

1.613 x 10^-7 = $\frac{3.142* d^{2} }{4}$

6.448 x 10^-7 = 3.142 x $d^{2}$

$d^{2}$ = $\sqrt{ 2.05*10^-7}$

d = 4.5 x 10^-4 m = <em>0.45 mm</em>

8 0

3 years ago