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dalvyx [7]
3 years ago
9

An object 16.8 cm tall is placed in front of a converging lens. A real image, 46 cm tall, is formed on the other side of the len

s. What is the magnification of the lens?
Physics
1 answer:
worty [1.4K]3 years ago
7 0

Answer:

2.74

Explanation:

Magnification = image distance/object distance

Mag = v/u

Given

v = 46cm

u = 16.8

Magnification = 46/16.8

Magnification = 2.74

Hence the magnification is 2.74

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