7 A steel sphere is released from a height

Physics

1 answer:

alisha [4.7K]3 years ago

4 0

Answer:

C 3.3 s

Explanation:

Given:

Δy = 9 m

v₀ = 0 m/s

a = ⅙ (9.8 m/s²) = 1.63 m/s²

Find: t

Δy = v₀ t + ½ at²

9 m = (0 m/s) t + ½ (1.63 m/s²) t²

t = 3.3 s

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A disk of a radius 50 cm rotates at a constant rate of 100 rpm. What distance in meters will a point on the outside rim travel d

Dmitry [639]

Answer:

the distance in meters traveled by a point outside the rim is 157.1 m

Explanation:

Given;

radius of the disk, r = 50 cm = 0.5 m

angular speed of the disk, ω = 100 rpm

time of motion, t = 30 s

The distance in meters traveled by a point outside the rim is calculated as follows;

$\theta = \omega t\\\\\theta = (100 \frac{rev}{\min} \times \frac{2\pi \ rad}{1 \ rev} \times \frac{1\min}{60 s} ) \times (30 s)\\\\\theta = 100 \pi \ rad\\\\d = \theta r\\\\d = 100\pi \ \times \ 0.5m\\\\d = 50 \pi \ m = 157.1 \ m$

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Answer:

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3 years ago

The electrical force on a 2-c charge is 60 n. the electric field where the charge is located is

Kazeer [188]

The electrical force acting on a charge q immersed in an electric field is equal to
$F=qE$
where
q is the charge
E is the strength of the electric field

In our problem, the charge is q=2 C, and the force experienced by it is
F=60 N
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At the end of a race a runner decelerates from a velocity of 8.90 m/s at a rate of 1.70 m/s2. (a) How far in meters does she tra

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Answer:

x=22.33m

Explanation:

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