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Natalka [10]
4 years ago
12

7 A steel sphere is released from a height

Physics
1 answer:
alisha [4.7K]4 years ago
4 0

Answer:

C 3.3 s

Explanation:

Given:

Δy = 9 m

v₀ = 0 m/s

a = ⅙ (9.8 m/s²) = 1.63 m/s²

Find: t

Δy = v₀ t + ½ at²

9 m = (0 m/s) t + ½ (1.63 m/s²) t²

t = 3.3 s

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An object is placed 96.5 cm from a glass lens (n = 1.51) with one concave surface of radius 24 cm and one convex surface of radi
poizon [28]

Answer:

image is vertical at distance -203.62 cm

magnification is 2.110

Explanation:

given data

n = 1.51

distance u = 96.5 cm

concave radius r1 = 24 cm

convex radius r2 = 19.1 cm

to find out

final image distance and magnification

solution

we will apply here lens formula to find focal length f

1/f = n-1 ( 1/r1 - 1/r2)   .......................1

put here all value

1/f = 1.51 -1 ( -1/24 + 1/19.1)

f = 183.43

so from lens formula

1/f = 1/v + 1/u     .............................2

put here all value and find v

1/183.43 = 1/v + 1/96.5

so

v = −203.62 cm

so here image is vertical at distance -203.62 cm

and

magnification are = -v /u

magnification =  203.62 / 96.5

magnification is 2.110

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4 years ago
Define velocity and also write their mathematical expression​
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what is the amplitude of the transverse wave modeled in the figure below if the height of a crest is 3 cm above is the resting p
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A = 3cm or 0.03m

Explanation:

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