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3 years ago

5

1 - 2r = 35 solve equation

1 answer:

lina2011 [118]3 years ago

6 0

Answer:

r=-17

Step-by-step explanation:

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If AD=6 and AB=24, find AC

ruslelena [56]

When a perpendicular is dropped from the right-angle (C) to the opposite side AB, the metric relations apply:
BD*BA=a^2 ..........................(1)
AD*AB=b^2...........................(2)
BD*DA=DC^2........................(3)

Given AD=6, AB=24, using metric relation (2) above, we have
b^2=6*24=144
=>
b=sqrt(144)=12

By the way, we conclude that this is a 30-60-90 triangle because b/AB=(1/2)=sin(B) => B=30 degrees.

Answer: b=12

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3 years ago

Maaz has a bank account with less than $400 in it. His bank pays no interest on that account, and charges $2 per month for each

Ede4ka [16]

Answer:

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Step-by-step explanation:

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3 years ago

The average (arithmetic mean) of y numbers is x. If 30 is added to the set of numbers, then the average will be x − 5. What is t

Alenkasestr [34]

Answer:

y = $\frac{1}{5}(x^{2}-35x)$

Step-by-step explanation:

Let the total numbers are n.

If the average of y numbers is x then we can form an equation

$\frac{y}{n}=x$

⇒ $\frac{n}{y}=\frac{1}{x}$

⇒ n = $\frac{y}{x}$ --------(1)

Now 30 is added to the set of numbers then average becomes (x - 5)

$\frac{y+30}{n+1}=(x-5)$

⇒ $\frac{(n+1)}{(y+30)}=\frac{1}{(x-5)}$

⇒ (n + 1) = $\frac{y+30}{x-5}$

⇒ n = $\frac{y+30}{x-5}$ - 1 ----- (2)

Now we equate the values of n from equation 1 and 2

$\frac{y}{x}$ = $\frac{y+30}{x-5}$ - 1

y(x - 5) = x(y + 30) - x(x - 5) [ By cross multiplication ]

xy - 5y = xy + 30x - x² + 5x

xy - xy - 5y = 35x - x²

-5y = 35x - x²

x² - 35x = 5y

y = $\frac{1}{5}(x^{2}-35x)$

6 0

3 years ago

Read 2 more answers