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Andrews [41]
3 years ago
13

1.625 rounded to the nearest hundredth

Mathematics
2 answers:
Mumz [18]3 years ago
4 0
1.625 rounded to the nearest hundredth is 1.63
lyudmila [28]3 years ago
4 0
The answer to your question is 1.63

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If the point is reflected across the x-axis, what is the location of the new point?
Neporo4naja [7]

Answer:

A) (5,3)yyhrfeusirjukgs

7 0
3 years ago
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Find the product. Tell what strategy you used. 8×25×23=
Novosadov [1.4K]
The answer is4600. I got this by multiplying 25 and 23 which is 575 then you multiply that by 8 which gives you 4600.

5 0
3 years ago
Suppose we have a bag with $10$ slips of paper in it. Eight slips have a $3$ on them and the other two have a $9$ on them. How m
8_murik_8 [283]

Value of the given statement:

  1. 4.36
  2. 5
  3. 6
  4. 38
<h3>What is Probability?</h3>

The area of mathematics known as probability deals with numerical descriptions of how likely it is for an event to happen or for a claim to be true. A number between 0 and 1 is the probability of an event, where, broadly speaking, 0 denotes the event's impossibility and 1 denotes its certainty.

According to the given information:

1) There are a total of 10 slips after adding.

8 slip with 3 on it

2 slips with 9  on it

 value = Probability of 3 x 3 plus Probability of 9 x 9.

=  (8 / 11)  x 3 + (2/ 11)  x 9

24 / 11 + 24 / 11 = 4.36

2 )No of total slips after addition = 12

8 slip with 3 on it

4 slips with 9  on it

 value = Probability of 3 x 3 plus Probability of 9 x 9.

=  (8 / 12)  x 3 + (4 / 12)  x 9

2 + 3 = 5

3 )Let n be the required number

No of total slips after addition = 10+n

8 slip with 3 on it

2 + n  slips with 9  on it

value = Probability of 3 x 3 plus Probability of 9 x 9.

=  (8 / 10+n )  x 3 + (2+n  / 10+n )  x 9 = 6

24 + 18 + 9n / 10 + n  = 6

42 + 9n = 60 + 6n

3 n = 18

n = 6

4 )Let n be the required number

No of total slips after addition = 10+n

8 slip with 3 on it

2 + n  slips with 9  on it

expectation value = probability of 3 x 3 + probability of 9 x 9

=  (8 / 10+n )  x 3 + (2+n  / 10+n )  x 9 = 8

24 + 18 + 9n / 10 + n  = 8

42 + 9n = 80 + 8n

n = 38

Minimum of 38 has to be added .

To know more about Probability visit:

brainly.com/question/17487084

#SPJ4

I understand that the question you are looking for is:

1:Suppose we have a bag with $10$ slips of paper in it. Eight slips have a $3$ on them and the other two have a $9$ on them. What is the expected value of the number shown if we add one additional $9$ to the bag? 2:Suppose we have a bag with $10$ slips of paper in it. Eight slips have a $3$ on them and the other two have a $9$ on them. What is the expected value of the number shown if we add two additional $9$'s (instead of just one) to the bag? 3:Suppose we have a bag with $10$ slips of paper in it. Eight slips have a $3$ on them and the other two have a $9$ on them. How many $9$'s do we have to add to make the expected value equal to $6$? 4:Suppose we have a bag with $10$ slips of paper in it. Eight slips have a $3$ on them and the other two have a $9$ on them. How many $9$'s do I have to add before the expected value is at least $8$?

4 0
2 years ago
three friends jogged last month. Richard jogged 9 miles last month. Jena jogged 2 times as many miles as Richard. Brian jogged 4
ANTONII [103]

Answer:

Jena=18 miles Brian=36 miles

Step-by-step explanation:

well if you add what Richard got and double it (9+9=18 or 9x2=18) you get how much Jena ran. then if u add (9+9+9+9=36 or 9x4=36) you get Brians miles he ran


8 0
3 years ago
Evaluate the difference quotient for the given function. Simplify your answer.
nasty-shy [4]

I suppose you mean

f(x) = \dfrac{x+5}{x+1}

Then

f(3) = \dfrac{3+5}{3+1} = \dfrac84 = 2

and the difference quotient is

\dfrac{f(x)-f(3)}{x-3} = \dfrac{\frac{x+5}{x+1}-2}{x-3} \\\\ \dfrac{f(x)-f(3)}{x-3} = \dfrac{\frac{x+5-2(x+1)}{x+1}}{x-3} \\\\ \dfrac{f(x)-f(3)}{x-3} = \dfrac{-x+3}{(x+1)(x-3)} \\\\ \dfrac{f(x)-f(3)}{x-3} = \boxed{-\dfrac{x-3}{(x+1)(x-3)}}

If it's the case that <em>x</em> ≠ 3, then (<em>x</em> - 3)/(<em>x</em> - 3) reduces to 1, and you would be left with

\dfrac{f(x)-f(3)}{x-3}\bigg|_{x\neq3} = -\dfrac1{x+1}

4 0
2 years ago
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