That'd be a total of 6 km east and 4 km north.
The distance traveled from Carol's starting point, along the path described, is
1 km + 4 km + 5 km = 10 km.
However, if you want the straight line distance from starting to end point, that would be found using the Pyth. Thm.:
sqrt [ (6 km)^2 + (4 km)^2 ] = sqrt(52) = 2sqrt(13) km
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Below is the solution:
xdy/dx = 4y
<span>xdy = 4ydx </span>
<span>∫ dy/y =∫ 4dx/x </span>
<span>ln(y) = 4ln(x) + C </span>
<span>y = e^[4ln(x)] e^C </span>
<span>y = e^[ln(x)^4] e^C </span>
<span>y = Cx^4 answer</span>
Answer:
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Step-by-step explanation:
Answer:
b
Step-by-step explanation: