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Lynna [10]
3 years ago
10

The line that goes through the point (5,-2) and (8,4)

Mathematics
1 answer:
scZoUnD [109]3 years ago
5 0
So for this equation you will want to graph the points (5,-2) and (8,4). I have taken the liberty of doing the graph for you.

With this I have put the two dots on the 2 locations they wanted. So then what you need to do is draw a straight line from dot one to dot two.

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Please help me!!!!! I need help!!!!!!!!!
Alex
The answer is 145 divided by tan 65 degrees.

Since the equation for tangent is opposite/adjacent, you can just plug the numbers in.

tan(65)=145/x (x being the height that you are trying to find)

tan(65) * x = 145

Then divide tan(65) to isolate the x and you get:

145/tan(65)

Hope this helps!
6 0
4 years ago
What is the lcm of 24de^2 and 36d^3e
lisov135 [29]
The lcm of this is 6d
7 0
4 years ago
Please help I have another question with the same criteria
kondaur [170]
The answer is 7 because it’s 7
5 0
3 years ago
Read 2 more answers
What is the third quartile of this set?<br> 165, 85, 105, 152, 144, 140, 160, 80
Oxana [17]
It’s the 5 and 6 numbers 152 and 144
4 0
4 years ago
Read 2 more answers
A concession stand at a sports stadium sells 600 bags of peanuts (each game) if the price of each bag is $4.00. For each $0.25 i
grin007 [14]

Answer:

Price = $4.50

Maximum revenue = $2,430

Step-by-step explanation:

The concession stand sells 600 bags of peanut at $4.00 (600, $4.00).

If there is a $1 increase in price, the number of bags old will decrease by 120, which mens that 480 bags of peanuts will be sold at $5.00 (480, $5.00).

Tracing a linear relationship between price and quantity sold with the two given points:

m = \frac{5-4}{480-600}\\ m=-\frac{1}{120}

P - P_0=m*(Q-Q_0)\\P-4.00=-\frac{1}{120} (Q-600)\\P= -\frac{1}{120}Q +9

The revenue function is given by the price multiplied by the quantity sold:

R=Q*P= (-\frac{1}{120}Q +9)*Q\\R=-\frac{1}{120}Q^2 +9Q

The value of 'Q' for which the derivate of the revenue function is zero, is the output level for which revenue is maximum:

R'=0=-\frac{2}{120}Q+9\\Q_{max} = 540\\P_{max} = -\frac{540}{120} +9\\P_{max} =\$4.50

The total revenue of 540 units at $4.50 per unit is:

R = \$4.50*540\\R=\$2,430

6 0
3 years ago
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