Since in this case we are
only using the variance of the sample and not the variance of the real population,
therefore we use the t statistic. The formula for the confidence interval is:
<span>CI = X ± t * s / sqrt(n) ---> 1</span>
Where,
X = the sample mean = 84
t = the t score which is
obtained in the standard distribution tables at 95% confidence level
s = sample variance = 12.25
n = number of samples = 49
From the table at 95%
confidence interval and degrees of freedom of 48 (DOF = n -1), the value of t
is around:
t = 1.68
Therefore substituting the
given values to equation 1:
CI = 84 ± 1.68 * 12.25 /
sqrt(49)
CI = 84 ± 2.94
CI = 81.06, 86.94
<span>Therefore at 95% confidence
level, the scores is from 81 to 87.</span>
Answer:
(1/2) (4k) + 12 = 2k + 12
X * y = -48
x + y = 8
y = -48/x
x -48/x = 8
x^2 - 48 = 8x
x^2 - 8x -48 = 0
x = 12
y = -4
Answer:
Base is 10, exponent is 15
Step-by-step explanation:
Answer:
1,359
Step-by-step explanation:
3% of 45,300 is 1,359
