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Citrus2011 [14]
3 years ago
15

Can I please have help I will mark brainly est

Mathematics
1 answer:
SpyIntel [72]3 years ago
8 0

Answer:

Hey mate......

Step-by-step explanation:

This is ur answer......

<h3>I believe its SQUARE! Cuz it says 4 right angles.....</h3>

Hope it helps!

mark me brainliest pls.....

Follow me! :)

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Why is it important to calculate the distance between two points on a cartesian coordinate plane?
Gwar [14]

Answer:

Derived from the Pythagorean Theorem, the distance formula is used to find the distance between two points in the plane. The Pythagorean Theorem,

a

2

+

b

2

=

c

2

, is based on a right triangle where a and b are the lengths of the legs adjacent to the right angle, and c is the length of the hypotenuse. The relationship of sides

|

x

2

−

x

1

|

and

|

y

2

−

y

1

|

to side d is the same as that of sides a and b to side c. We use the absolute value symbol to indicate that the length is a positive number because the absolute value of any number is positive. (For example,

|

−

3

|

=

3

. ) The symbols

|

x

2

−

x

1

|

and

|

y

2

−

y

1

|

indicate that the lengths of the sides of the triangle are positive. To find the length c, take the square root of both sides of the Pythagorean Theorem.

c

2

=

a

2

+

b

2

→

c

=

√

a

2

+

b

2

It follows that the distance formula is given as

d

2

=

(

x

2

−

x

1

)

2

+

(

y

2

−

y

1

)

2

→

d

=

√

(

x

2

−

x

1

)

2

+

(

y

2

−

y

1

)

2

We do not have to use the absolute value symbols in this definition because any number squared is positive.

A GENERAL NOTE: THE DISTANCE FORMULA

Given endpoints

(

x

1

,

y

1

)

and

(

x

2

,

y

2

)

, the distance between two points is given by

d

=

√

(

x

2

−

x

1

)

2

+

(

y

2

−

y

1

)

2

Step-by-step explanation:

4 0
3 years ago
Prove the following limit. lim x → 5 3x − 8 = 7 SOLUTION 1. Preliminary analysis of the problem (guessing a value for δ). Let ε
Temka [501]

\displaystyle\lim_{x\to5}3x-8=7

means to say that for any given \varepsilon>0, we can find \delta such that anytime |x-5| (i.e. the whenever x is "close enough" to 5), we can guarantee that |(3x-8)-7| (i.e. the value of 3x-8 is "close enough" to the limit value).

What we want to end up with is

|(3x-8)-7|=|3x-15|=3|x-5|

Dividing both sides by 3 gives

|x-5|

which suggests \delta=\dfrac\varepsilon3 is a sufficient threshold.

The proof itself is essentially the reverse of this analysis: Let \varepsilon>0 be given. Then if

|x-5|

and so the limit is 7. QED

8 0
3 years ago
Unit 8 homework 2 special right triangles
GenaCL600 [577]

Answer:

bro I cant see can you zoom in more im sorry j would answer if I could see

6 0
3 years ago
Find the difference 92/6-65/6
Volgvan
It is 27/6 or 4  1/2. you just need to subtract the numerators because you have a common denominator
5 0
3 years ago
Y = 3/4x + 6<br> y = 2x + 5
adoni [48]
The answer is (3:4) and use a period
7 0
3 years ago
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