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Katyanochek1 [597]
3 years ago
13

Question 3 of 10 Solve |x + 5|= 7.

Mathematics
2 answers:
quester [9]3 years ago
6 0

<u>Answer</u>:

  • x = 2 and -2

<u>Step-by-step</u><u> explanation</u>:

|x + 5| = 7

x + 5 = 7

x = 7 - 5

x = 2

|x + 5| = 7

-x + 5 = 7

-x = 7 - 5

-x = 2

x = -2

x = 2 and -2

damaskus [11]3 years ago
4 0

Answer:

|x + 5|= 7

-7<(x+5)<7

-7<x+5<7

-7-5<x+5-5<7-5

-12 < x <2

Step-by-step explanation:

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3 years ago
If
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It's easy to show that 7\tan(4x) is strictly increasing on x\in\left[0,\frac\pi8\right]. This means

M = \max \left\{7\tan(4x) \mid \dfrac\pi{16} \le x \le \dfrac\pi{12}\right\} = 7\tan(4x) \bigg|_{x=\pi/12} = 7\sqrt3

and

m = \min \left\{7\tan(4x) \mid \dfrac\pi{16} \le x \le \dfrac\pi{12}\right\} = 7\tan(4x) \bigg|_{x=\pi/16} = 7

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\implies \displaystyle \boxed{\frac{7\pi}{48}} \le \int_{\pi/16}^{\pi/12} 7\tan(4x) \, dx \le \boxed{\frac{7\sqrt3\,\pi}{48}}

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2 years ago
Find tan if sin=1/4 and falls in Quadrant 1
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and tan = prep / base  = 1 / root (15) 


7 0
3 years ago
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