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3 years ago

I need help with #2 (click the attached photo to view properly)I will mark Branliest

Mathematics

1 answer:

Shtirlitz [24]3 years ago

7 0

Hi there! :)

$\large\boxed{j(h(x))(2) = 31}$

Solve for j(h(x)):

h(x) = x² + 4

j(x) = 4x - 1

Substitute in h(x) into "x":

j(h(x)) = 4(x² + 4) - 1

j(h(x)) = 4x² + 16 - 1

j(h(x)) = 4x² + 15

Solve at x = 2:

4(2)² + 15 = 4(4) + 15 = 31.

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1 year ago

I need help with #2 (click the attached photo to view properly)I will mark Branliest​

I need help with #2 (click the attached photo to view properly)I will mark Branliest