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Dahasolnce [82]

3 years ago

7

A pendulum has 887 J of potential energy at the highest point of its swing. How much kinetic energy will it have at the bottom o

f its swing?

1 answer:

AlexFokin [52]3 years ago

3 0

At the bottom of its swing all of the potential energy has been converted to kinetic energy. It will have 887 J of kinetic energy.

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Consider a population of Pacific tree frogs (Pseudacris regilla). In this population of frogs, a single locus controls the produ

solniwko [45]

Answer: The answer is 62.32

Step-by-step explanation:

See attachment

6 0

3 years ago

On a diagram of the arena, the car park's length is 15 cm. The scale is 1:100.

faltersainse [42]

If a diagram has a scale of 1:100, that means that the real thing is 100 times larger. To find how long the real thing is, that means that we need to multiply the length on the diagram by 100. 100 * 15 is 1500. But, that is 1,500 cm. To convert it into meters, we need to divide by 100. That's because there's 100 centimeters in every meter. 1500/100 is 15, which means that the actual length of the car park is 15 meters.

8 0

3 years ago

Evaluate the function f(x) at the given numbers (correct to six decimal places).

statuscvo [17]

Answer:

The values of given function are shown in the below table.

Step-by-step explanation:

The given function is

$f(x)=\frac{x^2-5x}{x^2-x-20}$

Simplify the given function.

$f(x)=\frac{x(x-5)}{x^2-5x+4x-20}$

$f(x)=\frac{x(x-5)}{x(x-5)+4(x-5)}$

$f(x)=\frac{x(x-5)}{(x+4)(x-5)}$

Cancel out the common factor.

$f(x)=\frac{x}{x+4}$

Substitute x=5.5 in the above equation.

$f(5.5)=\frac{5.5}{5.5+4}$

$f(5.5)=\frac{5.5}{9.5}$

$f(5.5)=0.57894736842$

$f(5.5)\approx 0.578947$

Similarly find the value for all values of x.

The values of given function are shown in the below table.

8 0

3 years ago

Find the average rate of change for the given function from x = −1 to x = 2.

GREYUIT [131]

Well, if you look at the graph, when x = -1, y or f(x) = 4.

and when x = 2, y = 0.

$\bf slope = m = \cfrac{rise}{run} \implies 
\cfrac{ f(x_2) - f(x_1)}{ x_2 - x_1}\impliedby 
\begin{array}{llll}
average~rate\\
of~change
\end{array}\\\\
-------------------------------\\\\
\begin{cases}
x_1=-1\\
x_2=2
\end{cases}\implies \cfrac{f(2)-f(-1)}{2-(-1)}\implies \cfrac{0-4}{2+1}\implies \cfrac{-4}{3}$

8 0

3 years ago

A-b=b-a true or false

Annette [7]

Answer:

Depends

Step-by-step explanation:

If a and b = 0, then true

If a and b equal anything else then it is false

4 0

3 years ago

Read 2 more answers