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Rasek [7]
2 years ago
10

HELP ME I WILL GIVE POINTS

Mathematics
2 answers:
Anettt [7]2 years ago
8 0

Answer:

1.) 35

2.) -20

Step-by-step explanation:

OlgaM077 [116]2 years ago
4 0

Answer:

1. 32

3. -11

Step-by-step explanation:

(To meet character limit)

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What is the number of terms in this geometric series? 1+2+4+...+64
ioda

Answer:

7

Step-by-step explanation:

1,2 ,4,8,16,32,64

4 0
3 years ago
2- 1/2n=3n+16<br><br> I need you to solve the whole equation step by step
Alex Ar [27]

Answer:

n = -4

Step-by-step explanation:

2 - 1/2 n = 3n + 16

Combine the constants by subtracting 2 from both sides.

-1/2n = 3n + 14

Combine the variable by subtracting 3n from both sides.

-7/2n = 14

Multiply both sides by 2 to simplify the fraction.

-7n = 28

Isolate n by dividing by -7 on both sides.

n = -4

Check.

2 - 1/2(-4) = 3(-4) + 16

2 + 2 = -12 + 16

4 = 4

Your answer is correct.

3 0
3 years ago
Read 2 more answers
X=2x+3-17 how do i solve this
nikitadnepr [17]

Answer:

x=-4.67

Step-by-step explanation:

add like terms 3-17

then take x=2x-14

add 2x to both sides

3x=-14

divide by 3 and you get your answer

5 0
3 years ago
Read 2 more answers
The question in the picture is blurry so here it is :Laney used drinking straws in art to form of figure that had perpendicular
Nataliya [291]
D because perpendicular lines intersect at a right angle and D is the only shape with right angles.
5 0
3 years ago
Read 2 more answers
The number of texts per day by students in a class is normally distributed with a 
kobusy [5.1K]

Answer:

1, 2, 6

Step-by-step explanation:

The z score shows by how many standard deviations the raw score is above or below the mean. The z score is given by:

z=\frac{x-\mu}{\sigma} \\\\where\ x=raw\ score,\mu=mean, \ \sigma=standard\ deviation

Given that mean (μ) = 130 texts, standard deviation (σ) = 20 texts

1) For x < 90:

z=\frac{x-\mu}{\sigma} \\\\z=\frac{90-130}{20} =-2

From the normal distribution table, P(x < 90) = P(z < -2) = 0.0228 = 2.28%

Option 1 is correct

2) For x > 130:

z=\frac{x-\mu}{\sigma} \\\\z=\frac{130-130}{20} =0

From the normal distribution table, P(x > 130) = P(z > 0) = 1 - P(z < 0) = 1 - 0.5 = 50%

Option 2 is correct

3) For x > 190:

z=\frac{x-\mu}{\sigma} \\\\z=\frac{190-130}{20} =3

From the normal distribution table, P(x > 3) = P(z > 3) = 1 - P(z < 3) = 1 - 0.9987 = 0.0013 = 0.13%

Option 3 is incorrect

4)  For x < 130:

z=\frac{x-\mu}{\sigma} \\\\z=\frac{130-130}{20} =0

For x > 100:

z=\frac{x-\mu}{\sigma} \\\\z=\frac{100-130}{20} =-1.5

From the normal table, P(100 < x < 130) = P(-1.5 < z < 0) = P(z < 0) - P(z < 1.5) = 0.5 - 0.0668 = 0.9332 = 93.32%

Option 4 is incorrect

5)  For x = 130:

z=\frac{x-\mu}{\sigma} \\\\z=\frac{130-130}{20} =0

Option 5 is incorrect

6)  For x = 130:

z=\frac{x-\mu}{\sigma} \\\\z=\frac{160-130}{20} =1.5

Since 1.5 is between 1 and 2, option 6 is correct

5 0
3 years ago
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