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4 years ago

(2x3z2)3 ------------------ x3y4z2 * (x-4z3)

1 answer:

8 0

The rules of exponents tell you to add exponents in the numerator and subtract those in the denominator. A power of a power causes the exponent to be multiplied.

$\dfrac{(2x^{3}z^{2})^{3}}{x^{3}y^{4}z^2x^{-4}z^{3}}=2^{3}x^{(3\cdot3-3-(-4))}y^{-4}z^{(2\cdot3-2-3)}\\\\=\dfrac{8x^{10}z}{y^{4}}$

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What is 4 multiplied by 4/6

yawa3891 [41]

Okay,

1. Multiply 4 x 4.

2. Then Since 4 x 4 is 16 it would be 16 over 6 ( $\frac{16}{6}$ )

3. Then Simplify, 6 can go into 16 twice, being 12.

4. There is 4 left over, so put 4 over 6 ( $\frac{4}{6}$ )

5. Finally, simplify again, 4 can be divided by 2, so can 6, make it 2 over 3 ( $\frac{2}{3}$ )

Answer: 12 and 2 over 3 ( $12 \frac{2}{3}$ )

**Hope I Helped!**

5 0

4 years ago

Read 2 more answers

What is the ratio unknown amount (x) invested in company A to the know amount ($24) invested in company B? Write the answer as a

lara [203]

Answer:

X/24

Step-by-step explanation:

he ratio of the unknown amount (x) invested in company A to the known amount ($24) invested in company B is X/24

7 0

3 years ago

What are the domain and range of the function f(x)=5^x-3+1

Hunter-Best [27]

The domain is the set of all possible values of independent variable I.e of x. The range is the complete set of all possible resulting values of the dependent variable of i.e of y

8 0

3 years ago

Read 2 more answers

If logb2=x and logb3=y, evaluate the following in terms of x and y:

Alja [10]

$log_b{162} = x + 4y\\\\log_b324 = 2x+4y\\\\log_b\frac{8}{9} = 3x-2y\\\\\frac{log_b27}{log_b16} = 3y-4x$

Solution:

Given that,

$log_b2 = x\\\\log_b3 = y --------(i)$

Use the following log rules

Rule 1: $log_b(ac) = log_ba + log_bc$

Rule 2: $log_b\frac{a}{c} = log_ba - log_bc$

Rule 3: $log_ba^c = clog_ba$

$a) log_b{162}$

Break 162 down to primes:

$162 = 2^1 \times 3^4$

$log_b{162} =log_b 2^1. 3^4\\\\By\ rule\ 1\\\\ log_b{162} = log_b 2^1 +log_b 3^4\\\\By\ rule\ 3\\\\1log_b2 + 4log_b3\\\\1x+4y\\\\x+4y$

Thus we get,

$log_b162 = x + 4y$

$b) log_b 324$

Break 324 down to primes:

$324 = 2^2 \times 3^4$

$log_b324 = log_b 2^2.3^4\\\\By\ rule\ 1\\\\log_b324 = log_b2^2 + log_b3^4\\\\By\ rule\ 3\\\\log_b324 = 2log_b2 + 4log_b3\\\\From\ (i)\\\\log_b324 = 2x + 4y$

$c) log_b\frac{8}{9}$

By rule 2

$log_b\frac{8}{9} = log_b8 - log_b9\\\\log_b\frac{8}{9} = log_b 2^3 - log_b3^2\\\\By\ rule\ 3\\\\log_b\frac{8}{9} = 3 log_b2 - 2log_b3\\\\From\ (i)\\\\log_b\frac{8}{9} = 3x - 2y$

$d) \frac{log_b27}{log_b16}$

By rule 2

$\frac{log_b27}{log_b16} = log_b27 - log_b16\\\\ \frac{log_b27}{log_b16} = log_b3^3 - log_b2^4\\\\By\ rule\ 2\\\\ \frac{log_b27}{log_b16} = 3log_b3 - 4log_b2 \\\\From\ (i)\\\\\frac{log_b27}{log_b16} = 3y - 4x$

Thus the given are evaluated in terms of x and y

3 0

3 years ago

What is the factored form of the expression 9x^2 + 6x +1

liraira [26]

Answer:

(3x+1)^2

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers