Answer:
The positive difference between the a values is 0.5
Step-by-step explanation:
we know that
Both parabolas cross the x axis at (-4,0) and (6,0)
so
The general equation is

<em>Find the value of a in the first parabola</em>
The y-intercept is (0,-12)
so
For 
substitute




<em>Find the value of a in the second parabola</em>
The y-intercept is (0,-24)
so
For 
substitute




<em>Find the positive difference between the a values for the two functions</em>
so

Answer: more information?
Step-by-step explanation:
Answer:

If we increase the income by 1% that means that the new income would be 1.01 the before one and if we replace this we got:

And the net increase can be founded like this:
![Test score_f -Tet score_i = 557.8 +36.7842 Income- [557.8 +36.42 Income] = 36.7842 Income -36.42 Income = 0.3642](https://tex.z-dn.net/?f=%20Test%20score_f%20-Tet%20score_i%20%3D%20557.8%20%2B36.7842%20Income-%20%5B557.8%20%2B36.42%20Income%5D%20%3D%2036.7842%20Income%20-36.42%20Income%20%3D%200.3642)
So then the net increase would be:
C. 0.36 points
Step-by-step explanation:
For this case we have the following linear relationship obtained from least squares between test scores and the student-teacher ratio:

If we increase the income by 1% that means that the new income would be 1.01 the before one and if we replace this we got:

And the net increase can be founded like this:
![Test score_f -Tet score_i = 557.8 +36.7842 Income- [557.8 +36.42 Income] = 36.7842 Income -36.42 Income = 0.3642](https://tex.z-dn.net/?f=%20Test%20score_f%20-Tet%20score_i%20%3D%20557.8%20%2B36.7842%20Income-%20%5B557.8%20%2B36.42%20Income%5D%20%3D%2036.7842%20Income%20-36.42%20Income%20%3D%200.3642)
So then the net increase would be:
C. 0.36 points