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2 years ago

Write an equation of a line in slope intercept form given the line passes through the points (-5, 3) and (0, -7)

Mathematics

1 answer:

insens350 [35]2 years ago

7 0

Answer:

y=-2x-7

Step-by-step explanation:

Hope this helps, have a nice night! (^-^)

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nlexa [21]

Answer:

Step-by-step explanation:

(1,4)

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3 years ago

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Solve this system of equations: 5x + y = 7 20x + 2 = y

xz_007 [3.2K]

Answer:

x = 1/5, y = 6

Step-by-step explanation:

5x + y = 7

y = 7 - 5x

Set equations equal to each other to eliminate y

7 - 5x = 20x + 2

7 = 25x + 2

5 = 25x

x = 1/5

y = 7 - 5(1/5)

y = 7 - 1

y = 6

7 0

3 years ago

What does 2 2/3 x 3/11 equal?

kozerog [31]

Answer:

8/11

Step-by-step explanation:

2 2/3 = 8/3

8/3 x 3/11 = 24/33

24/33 = 8/11

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3 years ago

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line m passes through point (-2,-1) and is perpendicular to the graph of y=-2/3x+6. Line n is parallel to line m and passes thro

puteri [66]

Answer:

Hello...... here is a solution :

1 -

Hello:

the equation of "m" is : y = ax+b

the slope is a : a×(- 2/3) = -1......( perpendicular to a line : y=-2/3x+6 when the slope is -2/3 )

a = 3/2

the line " n" that passes through (4, - 3) and parallel to line "m" :

when the slope is 3/2 ( same slope )

the equation in slope-intercept form of the line" n" is :

y – (-3)= (3/2)(x – 4)

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3 years ago

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In a certain Algebra 2 class of 30 students, 19 of them play basketball and 12 of them play baseball. There are 8 students who p

Alenkinab [10]

Answer:

Probability that a student chosen randomly from the class plays basketball or baseball is $\frac{23}{30}$ or 0.76

Step-by-step explanation:

Given:

Total number of students in the class = 30

Number of students who plays basket ball = 19

Number of students who plays base ball = 12

Number of students who plays base both the games = 8

To find:

Probability that a student chosen randomly from the class plays basketball or baseball=?

Solution:

$P(A \cup B)=P(A)+P(B)-P(A \cap B)$ ---------------(1)

where

P(A) = Probability of choosing a student playing basket ball

P(B) = Probability of choosing a student playing base ball

P(A \cap B) = Probability of choosing a student playing both the games

Finding P(A)

P(A) = $\frac{\text { Number of students playing basket ball }}{\text{Total number of students}}$

P(A) = $\frac{19}{30}$ --------------------------(2)

Finding P(B)

P(B) = $\frac{\text { Number of students playing baseball }}{\text{Total number of students}}$

P(B) = $\frac{12}{30}$ ---------------------------(3)

Finding $P(A \cap B)$

P(A) = $\frac{\text { Number of students playing both games }}{\text{Total number of students}}$

P(A) = $\frac{8}{30}$ -----------------------------(4)

Now substituting (2), (3) , (4) in (1), we get

$P(A \cup B)= \frac{19}{30} + \frac{12}{30} -\frac{8}{30}$

$P(A \cup B)= \frac{31}{30} -\frac{8}{30}$

$P(A \cup B)= \frac{23}{30}$

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3 years ago