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2 years ago

Write an equation of a line in slope intercept form given the line passes through the points (-5, 3) and (0, -7)

Mathematics

1 answer:

insens350 [35]2 years ago

7 0

Answer:

y=-2x-7

Step-by-step explanation:

Hope this helps, have a nice night! (^-^)

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Jared and Pedro walk 1 mile in about 15 minutes. They can keep up pace for several hours. About how far they walk in 65 minutes

VladimirAG [237]

<h2>Answer:</h2>

Jared and Pedro walked a total of 4.3 miles

<h2>Step-by-step explanation:</h2>

The equation for distance is speed = distance ÷ time.
Rearrange the equation to make distance the subject:

(multiply both sides by time)

Distance = Speed × Time

Convert your numbers into suitable units:

1 mile ÷ 15 = 0.06m/minute

Finally, substitute the numbers into the equation and solve:

Distance = 0.06 × 65 = 4.3miles (rounded to the nearest decimal place)

<h2 />

4 0

2 years ago

A playground is 58 M wide and 91 what is the perimeter

cestrela7 [59]

Step-by-step explanation:

To get the perimeter, add up all of the sides.

So, the playground is a rectangle.

It has two sides measuring 58m, and two measuring 91m.

58+58+91+91=298

For the area, length x width

58x90=5278

5 0

1 year ago

How do I found the surface area of a 3 by 3 by 3 square?????

Dahasolnce [82]

3*3*3=9 perhaps?? And then it would be in Surface Area??

7 0

2 years ago

Read 2 more answers

Find polynomial whose zeros are 3 and -4

horrorfan [7]

Answer:

Simplest polynomial: x²+x-12

Step-by-step explanation:

zeroes of polynomial= 3,-4

Therefore,

f(3) =0

f(-4)=0.

By factor Theorem

(x-3) and (x+4) are factors

so simplest polynomial is

(x-3)(x+4)

= x² - 3x + 4x -12

= x² + x -12

Hope it helps

6 0

2 years ago

HELP!

maksim [4K]

Part A

$4x^2 -7x-15=0\\\\(4x+5)(x-3)=0\\\\x=-\frac{5}{4}, 3$

So, the x-intercepts are $\boxed{\left(-\frac{5}{4}, 0 \right), (3,0)}$

Part B

The vertex will be a minimum because the coefficient of $x^2$ is positive.

The x-coordinate of the vertex is $x=-\frac{-7}{2(4)}=\frac{7}{8}$

Substituting this back into the function, we get $f\left(\frac{7}{8} \right)=4\left(\frac{7}{8} \right)^2 -7\left(\frac{7}{8} \right)^2 -15=-\frac{289}{16}$

So, the coordinates of the vertex are $\boxed{\left(\frac{7}{8}, -\frac{289}{16} \right)}$

Part C

Plot the vertex and the x-intercepts and draw a parabola that passes through these three points.

The graph is shown in the attached image.

7 0

1 year ago