1) G.mars= 9.8x(1/3)=3.26
Vi=10 m/s , T=12 sec
Dis. = Vi(t)+1/2(g)(t)^2
(10)(12)+1/2(3.26)(12)^2= 354.72
2)V=500 m/s
Hmax= v^/2(g) = 500^2/2(9.8) = 12755.1
Answer:
The distance of the image produced by the concave mirror is 11.27 cm.
Explanation:
Given that,
Focal length = 8.40 cm
Distance between object and plane mirror = 11.0 cm
Distance between plane mirror and concave mirror = 22.0 cm
We need to calculate the object distance
We need to calculate the distance of the image
Using formula of distance of the image
Where, u = Object distance
f = focal length
Put the value into the formula
Hence, The distance of the image produced by the concave mirror is 11.27 cm.
<span>To answer this question, the equation that we will be using is:
y = A cos bx + c
where A = amplitude, b = 2 pi/Period, Period = 12 hrs, c = midline,
x = t and y = f(t)
A = 1/2 (Xmax - Xmin)
12 - 2 / 2 = 10/2 = 5
b = 2 pi / 12 = pi/6
c = 1/2 (Xmax + Xmin)
12+2/2 = 7
answer: f(t) = 5 cos pi/6 t + 7 </span>
Answer:
Explanation:
The gravitational force acting on the ball, F = 10 N (down) The air resistance acting on the ball, f = 1 N (up) We need to find the magnitude of net force acting on the ball. The net force is given by : F' = 9 N. So, the net force acting on the ball is 9 N in downward direction. Hence, this is the required solution