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goblinko [34]
4 years ago
6

A square plate of copper with 55.0 cm sides has no net charge and is placed in a region of uniform electric field of 82.0 kN/C d

irected perpendicularly to the plate.a. Find the charge density of each face of the plate.b. Find the total charge on each face.
Physics
1 answer:
Alex73 [517]4 years ago
7 0

Answer

given,

Side of copper plate, L = 55 cm

Electric field, E = 82 kN/C

a) Charge density,σ = ?

  using expression of charge density

 σ = E x ε₀

ε₀ is Permittivity of free space = 8.85 x 10⁻¹² C²/Nm²

now,

 σ = 82 x 10³ x 8.85 x 10⁻¹²

 σ = 725.7 x 10⁻⁹ C/m²

 σ = 725.7 nC/m²

change density on the plates are 725.7 nC/m² and -725.7 nC/m²

b) Total change on each faces

   Q = σ  A

   Q = 725.7 x 10⁻⁹ x 0.55²

   Q = 219.52 nC

Hence, charges on the faces of the plate are 219.52 nC and -219.52 nC

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romanna [79]

Answer:

\triangle V = 0.02484m^3

Explanation:

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To do this, we make use of cubic expansivity formula

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stich3 [128]

Answer:

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Explanation:

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Answer:

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