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Whitepunk [10]
3 years ago
10

Lacey has $36 to spend. She buys a pair of sunglasses for $14.89 and a hat for $9.33. Lacey buys a scarf with the remaining mone

y. How much does Lacey spend buying a scarf? (1 point)
$4.66
$7.44
$11.78
$24.22
Mathematics
2 answers:
stellarik [79]3 years ago
6 0

Answer: 11.78

Step-by-step explanation: You have to minus 36 by the cost of the hat and sunglasses.

Citrus2011 [14]3 years ago
4 0

Answer:

11.78

Step-by-step explanation:

Lacery has 36 dollars so she only has 36

she buy a pair of sunglasses for 14.89    14.89

ans buys a hat for 9.33                  

add 9.33 and 14.89 which u get 24.22

36.00

 minus

24.22 equals 11.78

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Agata [3.3K]

Answer:

1) v= 280 in^3 sa= 262 in^2

2) v= 80 in^3 sa= 120 in^2

3) v= 36 in^3 sa= 72 in^2

4) v= 240 in^3 sa= 252 in^2

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3 years ago
Grayson is deciding between two truck rental companies. Company A charges an initial fee of $40 for the rental plus $2 per mile
Alexandra [31]

Answer:

A is 10 dollar cheaper than B

Step-by-step explanation:

A : 40 dollars plus 45*2=90

90+40= 130 dollars

B:100 dollars 45*1=45

100+45= 145 dollars

5 0
3 years ago
Read 2 more answers
Determine whether the given vectors are orthogonal, parallel or neither. (a) u=[-3,9,6], v=[4,-12,-8,], (b) u=[1,-1,2] v=[2,-1,1
nevsk [136]

Answer:

a) u v= (-3)*(4) + (9)*(-12)+ (6)*(-8)=-168

Since the dot product is not equal to zero then the two vectors are not orthogonal.

|u|= \sqrt{(-3)^2 +(9)^2 +(6)^2}=\sqrt{126}

|v| =\sqrt{(4)^2 +(-12)^2 +(-8)^2}=\sqrt{224}

cos \theta = \frac{uv}{|u| |v|}

\theta = cos^{-1} (\frac{uv}{|u| |v|})

If we replace we got:

\theta = cos^{-1} (\frac{-168}{\sqrt{126} \sqrt{224}})=cos^{-1} (-1) = \pi

Since the angle between the two vectors is 180 degrees we can conclude that are parallel

b) u v= (1)*(2) + (-1)*(-1)+ (2)*(1)=5

|u|= \sqrt{(1)^2 +(-1)^2 +(2)^2}=\sqrt{6}

|v| =\sqrt{(2)^2 +(-1)^2 +(1)^2}=\sqrt{6}

cos \theta = \frac{uv}{|u| |v|}

\theta = cos^{-1} (\frac{uv}{|u| |v|})

\theta = cos^{-1} (\frac{5}{\sqrt{6} \sqrt{6}})=cos^{-1} (\frac{5}{6}) = 33.557

Since the angle between the two vectors is not 0 or 180 degrees we can conclude that are either.

c) u v= (a)*(-b) + (b)*(a)+ (c)*(0)=-ab +ba +0 = -ab+ab =0

Since the dot product is equal to zero then the two vectors are orthogonal.

Step-by-step explanation:

For each case first we need to calculate the dot product of the vectors, and after this if the dot product is not equal to 0 we can calculate the angle between the two vectors in order to see if there are parallel or not.

Part a

u=[-3,9,6], v=[4,-12,-8,]

The dot product on this case is:

u v= (-3)*(4) + (9)*(-12)+ (6)*(-8)=-168

Since the dot product is not equal to zero then the two vectors are not orthogonal.

Now we can calculate the magnitude of each vector like this:

|u|= \sqrt{(-3)^2 +(9)^2 +(6)^2}=\sqrt{126}

|v| =\sqrt{(4)^2 +(-12)^2 +(-8)^2}=\sqrt{224}

And finally we can calculate the angle between the vectors like this:

cos \theta = \frac{uv}{|u| |v|}

And the angle is given by:

\theta = cos^{-1} (\frac{uv}{|u| |v|})

If we replace we got:

\theta = cos^{-1} (\frac{-168}{\sqrt{126} \sqrt{224}})=cos^{-1} (-1) = \pi

Since the angle between the two vectors is 180 degrees we can conclude that are parallel

Part b

u=[1,-1,2] v=[2,-1,1]

The dot product on this case is:

u v= (1)*(2) + (-1)*(-1)+ (2)*(1)=5

Since the dot product is not equal to zero then the two vectors are not orthogonal.

Now we can calculate the magnitude of each vector like this:

|u|= \sqrt{(1)^2 +(-1)^2 +(2)^2}=\sqrt{6}

|v| =\sqrt{(2)^2 +(-1)^2 +(1)^2}=\sqrt{6}

And finally we can calculate the angle between the vectors like this:

cos \theta = \frac{uv}{|u| |v|}

And the angle is given by:

\theta = cos^{-1} (\frac{uv}{|u| |v|})

If we replace we got:

\theta = cos^{-1} (\frac{5}{\sqrt{6} \sqrt{6}})=cos^{-1} (\frac{5}{6}) = 33.557

Since the angle between the two vectors is not 0 or 180 degrees we can conclude that are either.

Part c

u=[a,b,c] v=[-b,a,0]

The dot product on this case is:

u v= (a)*(-b) + (b)*(a)+ (c)*(0)=-ab +ba +0 = -ab+ab =0

Since the dot product is equal to zero then the two vectors are orthogonal.

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Eva8 [605]
None of these because they all are 0
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Exactly 32% of the students in a school play a sport. Fifty students are randomly selected to determine the probability that, at
faltersainse [42]

A binomial probability density function should be used to represent the probability

<h3>How to determine the type of probability density?</h3>

The given parameters are:

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  • Number of students selected, p = 50
  • The probability, P = (x ≤ 15)

The proportion that plays sport indicates that

68% of the students do not play sport

So, we have two events, which are

  • Play sport
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When there are two possible events, then the binomial probability density function should be used

Read more about binomial probability density at:

brainly.com/question/15246027

#SPJ1

8 0
2 years ago
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