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Helga [31]
3 years ago
8

Which statement is most likely true about the place modeled I the diagrams? ​

Mathematics
2 answers:
barxatty [35]3 years ago
6 0

Answer:

The answer is below. I hope this is the answer your looking for.

Step-by-step explanation:

MA_775_DIABLO [31]3 years ago
4 0
Is this the question or what
You might be interested in
Help please, really confused​
Sever21 [200]

Answer:

  1a. y = 5x +3

  1b. y = -1/7x + 2

  1c. y = 2x +3

  2a. y = -1/2x +3; slope = -1/2, y-intercept = +3

  2b. y = 3/2x +6; slope = 3/2, y-intercept = +6

Step-by-step explanation:

Apparently the "y-intercept form" referred to is the one more commonly called "slope-intercept form." That form is ...

  y = mx + b . . . . . . . . m is the slope; b is the y-intercept

You arrive at this form by solving each equation for y. You do that the same way you solve any equation for any variable: undo what is done to the variable of interest.

In these general form equations, the y-variable term has a value multiplying y and some other terms added to that. First of all, you subtract the added terms (from both sides of the equation). This transforms ...

  ax +by +c = 0

into

  by = -ax -c

Next, you divide by the constant that is multiplying y. Of course all terms on both sides of the equation are divided by that, so you now have ...

  y = (-a/b)x -c/b

The slope is -a/b, and the y-intercept is -c/b.

___

1a. 5x -y +3 = 0

  -y = -5x -3 . . . . . subtract non-y terms

  y = 5x +3 . . . . . . divide by -1

__

1b. x +7y -14 = 0

  7y = -x +14 . . . . . subtract non-y terms

  y = -1/7x +2 . . . . .divide by 2

__

1c. 6x -3y +9 = 0

  -3y = -6x -9 . . . . subtract terms not containing y

  y = 2x +3 . . . . . . divide by -3

__

2a. x +2y -6 = 0

  2y = -x +6 . . . . . subtract non-y terms

  y = -1/2x +3 . . . . divide by 2 -- this is graphed as the red line below

__

2b. 3x -2y +12 = 0

  -2y = -3x -12 . . . . subtract non-y terms

  y = 3/2x +6 . . . . . divide by -2 -- this is graphed as the blue line below

_____

<em>Comment on the 2nd problem</em>

Of course, the y-intercept (constant term in slope-intercept form) is the point on the y-axis where the line crosses. The slope tells you the ratio of "rise" to "run". That is, a slope of -1/2 means the line drops one unit for each 2 units it goes to the right. A slope of 3/2 means the line increases (rises) by 3 units for each 2 units it goes to the right.

7 0
3 years ago
Please answer and explain the link below
Leviafan [203]

Answer:

See explanation.

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

<u>Algebra I</u>

  • Functions
  • Function Notation

<u>Calculus</u>

Limits

  • Right-Side Limit:                                                                                             \displaystyle  \lim_{x \to c^+} f(x)
  • Left-Side Limit:                                                                                               \displaystyle  \lim_{x \to c^-} f(x)

Limit Rule [Variable Direct Substitution]:                                                             \displaystyle \lim_{x \to c} x = c

Step-by-step explanation:

<u>Step 1: Define</u>

<em>Identify</em>

\displaystyle f(x) = \left \{ {{\sqrt{x + 1}, \ x < 3} \atop {5 - x, \ x \geq 3}} \right.

<u>Step 2: Find Right Limit</u>

  1. Substitute in variables [Right-Side Limit]:                                                      \displaystyle  \lim_{x \to 3^+} 5 - x
  2. Evaluate limit [Limit Rule - Variable Direct Substitution]:                           \displaystyle  \lim_{x \to 3^+} 5 - x = 5 - 3
  3. Subtract:                                                                                                         \displaystyle  \lim_{x \to 3^+} 5 - x = 2

∴ the right-side limit equals 2.

<u>Step 3: Find Left Limit</u>

  1. Substitute in variables [Left-Side Limit]:                                                       \displaystyle  \lim_{x \to 3^-} \sqrt{x + 1}
  2. Evaluate limit [Limit Rule - Variable Direct Substitution]:                           \displaystyle  \lim_{x \to 3^-} \sqrt{x + 1} = \sqrt{3 + 1}
  3. [√Radical] Add:                                                                                             \displaystyle  \lim_{x \to 3^-} \sqrt{x + 1} = \sqrt{4}
  4. [√Radical] Evaluate:                                                                                       \displaystyle  \lim_{x \to 3^-} \sqrt{x + 1} = 2

∴ the left-side limit equals 2.

<u>Step 4: Find Limit</u>

<em>The right and left-side limits are equal.</em>

∴  \displaystyle  \lim_{x \to 3} f(x) = 2

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Limits

Book: College Calculus 10e

4 0
3 years ago
How many feet are in 57 miles
mezya [45]

Answer:

300960

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
A rectangle with integer side lengths is divided into four smaller rectangles
devlian [24]

28/2=14

12/2=6

So it's half perimeter is 20

By trial and error the only possible solution is

8 * 12 = 96

3 0
3 years ago
1. Find the simple interest.
Juliette [100K]

Answer:

The first one is 648 and the second one is 11,600

Step-by-step explanation:

4 0
4 years ago
Read 2 more answers
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