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Kobotan [32]
2 years ago
7

Complete the steps to demonstrate why you multiply by the reciprocal when dividing fractions. Find 1/4 ÷ 3/8. ..................

..................................................................................................................................
Step 1:rewrite it as 1/4/3/8. ....................................................................................................................................................Step 2:multiply the numerator and the denominator by the reciprocal of blank /blank. 1/4/3/8=1/4/3/8×blank/blank/ blank /blank.                                                                     ....................................................................................................................................................Step 3:simplify the denominator 1/4×8/3/blank                                                                  .................................................................................................................................................Step 4:simplify the fraction blank/blank ×blank/blank.               
Mathematics
1 answer:
Nataliya [291]2 years ago
3 0
<span>To complete the steps to demonstrate why you multiply by the reciprocal when dividing fractions.

To find
\frac{1}{4}\div\frac{3}8}

Step 1:
Rewrite it as
\frac{\frac{1}{4}}{\frac{3}{8}}.


Step 2:
Multiply the numerator and the denominator by the reciprocal of
\frac{3}{8}.</span><span>

</span><span>\frac{\frac{1}{4}}{\frac{3}{8}}=\frac{\frac{1}{4}}{\frac{3}{8}}\times\frac{\frac{8}{3}}{\frac{8}{3}}


Step 3:
Simplify the denominator
\frac{\frac{1}{4}\times\frac{8}{3}}{1}                                                                 

Step 4:
Simplify the fraction
</span><span>\frac{1}{4}\times\frac{8}{3}.

We complete the solution as follows:
</span><span><span>\frac{1}{4}\times\frac{8}{3}=\frac{1\times8}{4\times3}\\ \\=\frac{8}{12}=\frac{4\times2}{4\times3}=\frac{2}{3}</span></span>
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What is an equation of the line that passes through the point (2,−6) and is parallel to the line x-2y=8
lana [24]

Answer:

y=\frac{1}{2}x-7, or x-2y=14

Step-by-step explanation:

Hi there!

We want to find the equation of the line that passes through the point (2, -6) and is parallel to the line x-2y=8

First, we need to find the slope of x-2y=8, since parallel lines have the same slopes

We can convert the equation from standard form (ax+by=c) to slope-intercept form (y=mx+b, where m is the slope and b is the y intercept), in order to help us find the slope of the line

Start by subtracting x from both sides

-2y=-x+8

Divide both sides by -2

y=\frac{1}{2}x-4

The slope of the line x-2y=8 is 1/2

It's also the slope of the line parallel to it.

Since we know the slope of the line, we can plug it into the equation for slope intercept form:

y=\frac{1}{2}x+b

Now we need to find b.

As the equation of the line passes through (2, -6), we can use it to help solve for b

Substitute -6 as y and 2 as x:

-6=\frac{1}{2}(2)+b

Multiply

-6=1+b

Subtract 1 from both sides

-7=b

Substitute -7 as b into the equation:

y=\frac{1}{2}x-7

The equation can be left as that, or you can convert it into standard form if you wish.

In that case, you will need to move 1/2x to the other side:

-\frac{1}{2}x+y=-7

A rule about the coefficients a, b, and c in standard form is that a (coefficient in front of x) CANNOT be negative, and every coefficient must be an integer (a whole number, not a fraction or decimal).

So multiply both sides by -2 in order to clear the fraction, as well as change the sign of a

x-2y=14

Hope this helps!

8 0
2 years ago
Solve the equation for exact solutions over the interval​ [0, 2π​).
quester [9]

Answer:

\displaystyle x=\left\{0, \frac{2\pi}{3}, \frac{4\pi}{3}\right\}

Step-by-step explanation:

We want to solve the equation:

-2\cos^2(x)=-\cos(x)-1

Over the interval [0, 2π).

First, notice that this is in quadratic form. So, to make things simpler, we can let <em>u</em> = cos(x). Substitute:

-2u^2=-u-1

Rearrange:

2u^2-u-1=0

Factor:

(2u+1)(u-1)=0

Zero Product Property:

2u+1=0\text{ or } u-1=0

Solve for each case:

\displaystyle u=-\frac{1}{2}\text{ or } u=1

Back-substitute:

\displaystyle \cos(x)=-\frac{1}{2}\text{ or } \cos(x)=1

Using the unit circle:

\displaystyle x=\left\{0, \frac{2\pi}{3}, \frac{4\pi}{3}\right\}

7 0
3 years ago
Use the Quadratic Formula to find the exact solutions of x2 + 7x - 4 = 0.
sladkih [1.3K]

Answer:

The solution of equation x^2+7x-4=0 is 0.53,-7.53.

Step-by-step explanation:

Given : Quadratic equation x^2+7x-4=0

To find : The solution of equation ?

Solution :

The solution of the quadratic equation ax^2+bx+c=0 is x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}

Here, a=1, b=7 and c=-4.

Substitute the values,

x=\frac{-7\pm\sqrt{7^2-4(1)(-4)}}{2(1)}

x=\frac{-7\pm\sqrt{65}}{2}

x=\frac{-7+\sqrt{65}}{2},\frac{-7-\sqrt{65}}{2}

x=0.53,-7.53

Therefore, the solution of equation x^2+7x-4=0 is 0.53,-7.53.

3 0
3 years ago
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