What is the probability of obtaining two tails when flipping a coin

1 answer:

8 0

First make a sample space:
HT, HH, TH, TT
There are 4 probabilities and only one obtains 2 tails.
The probability is 1/4 chance in getting tails twice when flipping a coin.

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Multiply the polynomials (x+3)(x^2-6x+5)

LekaFEV [45]

Answer:

$\huge\boxed{x^3-3x^2-13x+15}$

Step-by-step explanation:

$\text{Use FOIL:}\\\\(a+b)(c+d)=ac+ad+bc+bd$

$(x+3)(x^2-6x+5)\\\\=(x)(x^2)+(x)(-6x)+(x)(5)+(3)(x^2)+(3)(-6x)+(3)(5)\\\\=x^3-6x^2+5x+3x^2-18x+15\\\\\text{combine like terms}\\\\=x^3+(-6x^2+3x^2)+(5x-18x)+15\\\\=x^3-3x^2-13x+15$

3 0

3 years ago

What is the solution of the proportion 7/9 = m/27

ki77a [65]

7 M
--- = ----
9 27
cross multiply (7*27=189) and divide (189/9=21)
M = 21

3 0

4 years ago

Please help <br> thanksss

expeople1 [14]

Answer: y = - $\frac{2}{3}$ x - 6

Step-by-step explanation:

The line crosses the y intercept at y = -6

The slope of the graph looks negative, as it extends from the top left quadrant to the bottom right quadrant.

A key trick is to use rise/run to figure out the slope:

Between each dot on the line, it rises 2 and runs -3 (negative because the direction is left).

So your equation would be: y = - $\frac{2}{3}$ x - 6

7 0

4 years ago

Consider the sequence: 3, 8, 13, 18, 23, ...The recursive formula for this sequence is:an = an-1 + 5In a COMPLETE sentence, expl

Akimi4 [234]

Answer:

$a_8=38$

Step-by-step explanation:

<u>Recursive sequence </u>

In a recursive sequence formula, each term $a_n$ is computed as a function of one or more previous terms. In the formula

$a_n=a_{n-1}+5$

n is the number of the term we want to calculate. If n=8, then the formula becomes

$a_8=a_{7}+5$

We can see $a_{n-1}$ is the previous term. It means we need $a_7$ to be able to compute $a_8$ . But we also need $a_6$ to compute $a_7$ and so on until some known data is reached. The question provides five terms, $a_5=23.$