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4 years ago

What is the probability of obtaining two tails when flipping a coin

1 answer:

8 0

First make a sample space:
HT, HH, TH, TT
There are 4 probabilities and only one obtains 2 tails.
The probability is 1/4 chance in getting tails twice when flipping a coin.

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What is the ratio of beaks to wings in a flock of birds

ziro4ka [17]

The ratio of beaks to wings in a flock of birds is 1:2

5 0

3 years ago

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What are the coordinates of point B on AC Such that the ratio of AB to AC is 5:6

Oksi-84 [34.3K]

Answer:

$\vec B = \left(x_{A}+\frac{5}{6}\cdot (x_{C}-x_{A}), y_{A}+\frac{5}{6}\cdot (y_{C}-y_{A}), z_{A}+\frac{5}{6}\cdot (z_{C}-z_{A})\right)$

Step-by-step explanation:

Let suppose that A, B, and C have the following points with respect to origin in the Euclidean space:

$\vec A = (x_{A}, y_{A}, z_{A})$

$\vec B = (x_{B}, y_{B}, z_{B})$

$\vec C = (x_{C}, y_{C}, z_{C})$

Besides, let consider that locations of A and B are currently known. The ratio is:

$\frac{AB}{AC} = \frac{5}{6}$

$AB = \frac{5}{6} \cdot AC$

Vectorially speaking, expression can be rewritten in the following terms:

$\overrightarrow{AB} = \frac{5}{6}\cdot \overrightarrow{AC}$

$(x_{B}-x_{A}, y_{B}-y_{A}, z_{B}-z_{A}) = \frac{5}{6}\cdot (x_{C}-x_{A}, y_{C}-y_{A}, z_{C}-z_{A})$

Now, each side of the equation is summed vectorially by $\vec A$ and coordinates of point B are finally found:

$\vec B = \left(x_{A}+\frac{5}{6}\cdot (x_{C}-x_{A}), y_{A}+\frac{5}{6}\cdot (y_{C}-y_{A}), z_{A}+\frac{5}{6}\cdot (z_{C}-z_{A})\right)$

3 0

3 years ago

WILL GIVE BRAINLIEST

horrorfan [7]

F(x)= 3x + 1
f(x)= 3(3) + 1
= 9 + 1
= 10

g(x)= 4x - 5
= 4(3) - 5
= 12 - 5
= 7

So... A. f(x) is greater when x=3

7 0

3 years ago

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The pool was full with the dump 60 inches the water was drained out at a rate of 8 in./h right the function for this situation

Kobotan [32]

The pool was full with the dump 60 inches the water was drained out at a rate of 8 in./h right the function for this situation

Let

y -----> the number of inches in the water

x -----> the time in hours

we have that

y=60-8x -----> equation taht represent this situation

3 0

1 year ago

8 - (7/10)t = 6 - (1/5)t

rosijanka [135]

Answer:

t = 4

Step-by-step explanation:

Solve for t:

8 - (7 t)/10 = 6 - t/5

Hint: | Put the fractions in 8 - (7 t)/10 over a common denominator.

Put each term in 8 - (7 t)/10 over the common denominator 10: 8 - (7 t)/10 = 80/10 - (7 t)/10:

80/10 - (7 t)/10 = 6 - t/5

Hint: | Combine 80/10 - (7 t)/10 into a single fraction.

80/10 - (7 t)/10 = (80 - 7 t)/10:

1/10 (80 - 7 t) = 6 - t/5

Hint: | Put the fractions in 6 - t/5 over a common denominator.

Put each term in 6 - t/5 over the common denominator 5: 6 - t/5 = 30/5 - t/5:

(80 - 7 t)/10 = 30/5 - t/5

Hint: | Combine 30/5 - t/5 into a single fraction.

30/5 - t/5 = (30 - t)/5:

(80 - 7 t)/10 = (30 - t)/5

Hint: | Make (80 - 7 t)/10 = (30 - t)/5 simpler by multiplying both sides by a constant.

Multiply both sides by 10:

(10 (80 - 7 t))/10 = (10 (30 - t))/5

Hint: | Cancel common terms in the numerator and denominator of (10 (80 - 7 t))/10.

(10 (80 - 7 t))/10 = 10/10×(80 - 7 t) = 80 - 7 t:

80 - 7 t = (10 (30 - t))/5

Hint: | In (10 (30 - t))/5, divide 10 in the numerator by 5 in the denominator.

10/5 = (5×2)/5 = 2:

80 - 7 t = 2 (30 - t)

Hint: | Write the linear polynomial on the left hand side in standard form.

Expand out terms of the right hand side:

80 - 7 t = 60 - 2 t

Hint: | Move terms with t to the left hand side.

Add 2 t to both sides:

2 t - 7 t + 80 = (2 t - 2 t) + 60

Hint: | Look for the difference of two identical terms.

2 t - 2 t = 0:

2 t - 7 t + 80 = 60

Hint: | Group like terms in 2 t - 7 t + 80.

Grouping like terms, 2 t - 7 t + 80 = 80 + (2 t - 7 t):

80 + (2 t - 7 t) = 60

Hint: | Combine like terms in 2 t - 7 t.

2 t - 7 t = -5 t:

-5 t + 80 = 60

Hint: | Isolate terms with t to the left hand side.

Subtract 80 from both sides:

(80 - 80) - 5 t = 60 - 80

Hint: | Look for the difference of two identical terms.

80 - 80 = 0:

-5 t = 60 - 80

Hint: | Evaluate 60 - 80.

60 - 80 = -20:

-5 t = -20

Hint: | Divide both sides by a constant to simplify the equation.

Divide both sides of -5 t = -20 by -5:

(-5 t)/(-5) = (-20)/(-5)

Hint: | Any nonzero number divided by itself is one.

(-5)/(-5) = 1:

t = (-20)/(-5)

Hint: | Reduce (-20)/(-5) to lowest terms. Start by finding the GCD of -20 and -5.

The gcd of -20 and -5 is -5, so (-20)/(-5) = (-5×4)/(-5×1) = (-5)/(-5)×4 = 4:

Answer: t = 4

6 0

3 years ago