2 years ago

Can some one help me with Freshmen Algebra I kinda forgot how to do something and I need a refresher.

Mathematics

1 answer:

padilas [110]2 years ago

7 0

Answer:

Wheres the question?

Step-by-step explanation:

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A. 2860

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2 years ago

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Triangle HIJ is similar to triangle KLM. Find the measure of side MK. Round your answer to the nearest tenth.

AnnZ [28]

Answer:

$MK\approx 87.7$

Step-by-step explanation:

By definition, similar polygons have corresponding sides in a constant proportion. Therefore, we can set up the following proportion (ratio of corresponding sides) to solve for $MK$ :

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Find the modulus of the complex number 6-2i

Papessa [141]

Answer:

The modulus of the complex number 6-2i is:

$|z|\:=2\sqrt{10}$

Step-by-step explanation:

Given the number

$6-2i$

We know that

$z = x + iy$

where x and y are real and $\sqrt{-1}=i$

The modulus or absolute value of z is:

$|z|\:=\sqrt{x^2+y^2}$

Therefore, the modulus of $6-2i$ will be:

$z=6-2i$

$z=6+(-2)i$

$|z|\:=\sqrt{x^2+y^2}$

$|z|\:=\sqrt{6^2+\left(-2\right)^2}$

$=\sqrt{6^2+2^2}$

$=\sqrt{36+4}$

$=\sqrt{40}$

$=\sqrt{2^2}\sqrt{2\cdot \:5}$

$=2\sqrt{2\cdot \:5}$

$=2\sqrt{10}$

Therefore, the modulus of the complex number 6-2i is:

$|z|\:=2\sqrt{10}$

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<em>* Hopefully this helps:) </em>

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