It is not equal to a ratio of 2 \ 5 it is equal to<span> 6 to 1,</span>5 to 1, 3 to 2,
2 to 3 ,<span>1 to 6</span>
First one is the correct answer
66.666666 repeated decimal
You would keep the 66 as is, and divide 2 by 3. That equals 0.66666666666 repeated, so the answer would be 66.666666 (rounded: 66.67)
The dP/dt of the adiabatic expansion is -42/11 kPa/min
<h3>How to calculate dP/dt in an adiabatic expansion?</h3>
An adiabatic process is a process in which there is no exchange of heat from the system to its surrounding neither during expansion nor during compression
Given b=1.5, P=7 kPa, V=110 cm³, and dV/dt=40 cm³/min
PVᵇ = C
Taking logs of both sides gives:
ln P + b ln V = ln C
Taking partial derivatives gives:

Substitutituting the values b, P, V and dV/dt into the derivative above:
1/7 x dP/dt + 1.5/110 x 40 = 0
1/7 x dP/dt + 6/11 = 0
1/7 x dP/dt = - 6/11
dP/dt = - 6/11 x 7
dP/dt = -42/11 kPa/min
Therefore, the value of dP/dt is -42/11 kPa/min
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Answer:
I think it would be 12
Step-by-step explanation: