Question

Write the equation of a line parallel to y=3x-2 and goes through the point (-6,-11)

Answer 1

Answer:

The equation of the line would be y = 3x + 7

Step-by-step explanation:

In order to find the equation of the new line, start by taking the slope from the first line (3). This is because parallel lines have the same slope. Next, we use that and the point in point-slope form.

y - y1 = m(x - x1)

y - -11 = 3(x - -6)

y + 11 = 3(x + 6)

y + 11 = 3x + 18

y = 3x + 7