Suppose that 10% of all steel shafts produced by a certain process are nonconforming but can be reworked (rather than having to
1 answer:
Answer:
0.9905,0.9837,0.8066
Step-by-step explanation:
Given that 10% of all steel shafts produced by a certain process are nonconforming but can be reworked (rather than having to be scrapped).
Each shaft is independent of the other and probability for non conforming is the same for each trial.
Hence X the among these that are nonconforming and can be reworked. is Bin with n =200 and p = 0.10
a)
b)
c)
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Answer:
Step-by-step explanation:
<h3>Answer ↓</h3>
y=-2x+5
<h3>Calculations ↓</h3>First of all we need to determine the slope of the line perpendicular to y = 1/2x - 5 .
The slopes of perpendicular lines are opposite reciprocals.
So we take 1/2 , turn it over , and change it's sign :
The slope of the line perpendicular to y = 1/2x-5 is -2 .
Since we're also given a point that the line crosses , we can write the line's equation in point - slope form :
y-y₁=m(x-x₁)
y-7=-2(x-(-1)
y-7=-2(x+1)
Now convert to slope intercept :
y-7=-2x-2
add 7 on both sides :
<h3>y = -2x+5</h3>