The scuba diver's position relative to sea level after the 4.6 minutes is 5.1 ft.
Given:
A scuba diver descends in the water at a rate of 23 1/2 feet per minute for 2.6 minutes.
A scuba diver ascends at a rate of 28 feet per minute for 2 minutes after seeing a big fish.
To find :
The scuba diver's position relative to sea level after the 4.6 minutes.
Solution:
Rate of a scuba diver descending in the water for 2.6 minutes = 
Distance covered by a scuba diver in 2.6 minutes = 
Rate of a scuba diver ascending for 2 minutes = 
Distance covered by a scuba diver in 2 minutes = 
The position of scuba diver after 4.6 minutes relative to sea level:
The scuba diver's position relative to sea level after the 4.6 minutes is 5.1ft.
Learn more about ascending rate and descending rate here:
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The answer is 3 because the length of the box is 10, the width is 5, and the height is 3.
10 * 6 = 60 by the time Zach joins so 125-60 = 65
Now 6 (lexie) +7 (zach) = 13 (together) and 65/13 = 5.
6*5 = 30 and 7*5 = 35. 35+30 = 65
Your answer is 5.
Answer:
a) 2.5 shots
b) 59.4 shots
c) 4.87 shots
Step-by-step explanation:
Probability of making the shot = 0.6
Probability of missing the shot = 0.4
a) The expected number of shots until the player misses is given by:
The expected number of shots until the first miss is 2.5
b) The expected number of shots made in 99 attempts is:
He is expected to make 59.4 shots
c) Let "p" be the proportion shots that the player make, the standard deviation for n = 99 shots is:
The standard deviation is 4.87 shots.
