Answer:
<em>1</em><em>0</em><em>4</em><em>7</em><em>.</em><em>7</em><em>8</em>
<em>nearest</em><em> </em><em>tens</em><em> </em><em>is</em><em> </em><em>1</em><em>0</em><em>4</em><em>7</em><em>.</em><em>7</em><em>0</em>
<em>near</em><em>est</em><em> </em><em>thousandth</em><em> </em><em>is</em><em> </em><em>1</em><em>0</em><em>5</em><em>0</em><em>.</em><em>7</em><em>8</em>
Answer:
B. 1.65 L
Explanation:
Step 1: Write the balanced equation
2 SO₂(g) + O₂(g) ⇒ 2 SO₃(g)
Step 2: Calculate the moles of SO₂
The pressure of the gas is 1.20 atm and the temperature 25 °C (298 K). We can calculate the moles using the ideal gas equation.
P × V = n × R × T
n = P × V / R × T
n = 1.20 atm × 1.50 L / (0.0821 atm.L/mol.K) × 298 K = 0.0736 mol
Step 3: Calculate the moles of SO₃ produced
0.0736 mol SO₂ × 2 mol SO₃/2 mol SO₂ = 0.0736 mol SO₃
Step 4: Calculate the volume occupied by 0.0736 moles of SO₃ at STP
At STP, 1 mole of an ideal gas occupies 22.4 L.
0.0736 mol × 22.4 L/1 mol = 1.65 L
Answer:
1.10 g H2
Explanation:
I took the test and got the answer correct
