Okay so the answer will be.
Mass of KNO₃ : = 40.643 g
<h3>Further explanation</h3>
Given
28.5 g of K₃PO₄
Required
Mass of KNO₃
Solution
Reaction(Balanced equation) :
2K₃PO₄ + 3 Ca(NO₃)₂ = Ca₃(PO₄)₂ + 6 KNO₃
mol K₃PO₄(MW=212,27 g/mol) :
= mass : MW
= 28.5 : 212,27 g/mol
= 0.134
Mol ratio of K₃PO₄ : KNO₃ = 2 : 6, so mol KNO₃ :
= 6/2 x mol K₃PO₄
= 6/2 x 0.134
= 0.402
Mass of KNO₃ :
= mol x MW KNO₃
= 0.402 x 101,1032 g/mol
= 40.643 g
Answer:
A. 32.06 g/mol
Explanation:
The molar mass units are always g/mol
What are the variables you have? I can't answer if I don't know? Haha. :)
Answer:
pill need to taken for completing dosage of
mg
Explanation:
Total dosage of medicine to be taken in a day
mg
Total weight of one pill
mg
Number of pills required is equal to total dosage of medicine divided by the weight of one pill.
Hence,
Number of pills
