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Rasek [7]
3 years ago
12

Which example is not a kind of symbiosis? A. estivation B. commensalism C. parasitism D. mutualism

Chemistry
2 answers:
aliya0001 [1]3 years ago
4 0
Your answer is estivation.
7nadin3 [17]3 years ago
4 0

Answer:

C. parasitism

Explanation:

Symbiosis is an interspecific ecological interaction, that is, between organisms of different species, occurring in a compulsory and harmonious manner, allowing reciprocal advantages for the species involved. This association is permanent, causing dependence indispensable to the survival of the parties, and can no longer detach from each other, due to the collaboration that each exerts on the metabolism of its dependent, probably harmful if they were separated.

Parasitism is an association between two organisms, but it is the type of association that does not promote benefits to both living organisms, on the contrary, in parasitism an organism causes a malfunction in the body of another organism, but its development is favored. For this reason, parasitism cannot be considered a kind of symbiosis.

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What is the pH of a sample with [OH-] = 2.5 x 10-11 M?
sveticcg [70]

Answer:

The pH of the sample is 3,4.

Explanation:

We calculate the pOH from the formula pOH = -log (OH-). We know that for all aqueous solutions: pH + pOH = 14, and from there we clear pH:

pOH= -log (OH-)=10,60

pH + pOH = 14

pH + 10,60 = 14

pH=14 -10,60

<em>pH=3,4</em>

3 0
3 years ago
An aqueous solution contains 0.23 M potassium hypochlorite.
Arturiano [62]

Answer:

0.22 mol HClO, 0.11mol HBr.

0.25mol NH₄Cl, 0.12 mol HCl

Explanation:

A buffer is defined as a mixture in solution between weak acid and its conjugate base or vice versa.

Potassium hypochlorite (KClO) could be seen as conjugate base of HClO (Weak acid). That means the addition of <em>0.22 mol HClO  </em>will convert the solution in a buffer. HBr reacts with KClO producing HClO, thus, <em>0.11mol HBr</em> will, also, convert the solution in a buffer. 0.23 mol HBr will react completely with KClO and in the solution you will have only HClO, no a buffering system.

Ammonia (NH₃) is a weak base and its conjugate base is NH₄⁺. That means the addition of <em>0.25mol NH₄Cl</em> will convert the solution in a buffer. Also, NH₃ reacts with HCl producing NH₄⁺. Thus, addition of<em> 0.12 mol HCl</em>  will produce NH₄⁺. 0.25mol HCl consume all NH₃.

5 0
3 years ago
Which is nitrated faster toluene or nitrobenzoate and why<br>​
Nataly_w [17]
The Malcontents' major complaints were that the Trustees had placed too many limitations on the ownership of land, the right to make and to buy alcohol, and the right to own slaves.
4 0
3 years ago
Carbon-14 has a half-life of 5,730 years. It is used in "carbon dating" to determine the age of once living organisms. How much
Nookie1986 [14]

Answer:

18 grams

Explanation:

Because 17,190 yrs divided by the amount of years it takes for a half-life to occur is 3. So 3 half life’s happen, so you divide 144/2 once, equaling 72. You divide 72/2 again (another half-life) and you get 36. You then calculate the third half life by dividing 36/2 which equals 18 grams.

7 0
3 years ago
Calculate the [H+]
ELEN [110]

[H⁺]=6.696 x 10⁻⁵

pH = 4.174

<h3> Further explanation </h3>

Given

The concentration of 0.000295 M (2.95 x 10⁻⁴ M) butanoic acid solution

Required

the [H+]  and pH

Solution

Butanoic acid is the carboxylic acid group. Carboxylic acids are weak acids

For weak acid :

\tt [H^+]=\sqrt{Ka.M}

Input the value :

[H⁺]=√1.52 x 10⁻⁵ x 2.95 x 10⁻⁴

[H⁺]=6.696 x 10⁻⁵

pH = - log [H⁺]

pH = - log 6.696 x 10⁻⁵

pH = 5 - log 6.696

pH = 4.174

5 0
3 years ago
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