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3 years ago

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Which example is not a kind of symbiosis? A. estivation B. commensalism C. parasitism D. mutualism

2 answers:

aliya0001 [1]3 years ago

4 0

Your answer is estivation.

7nadin3 [17]3 years ago

4 0

Answer:

C. parasitism

Explanation:

Symbiosis is an interspecific ecological interaction, that is, between organisms of different species, occurring in a compulsory and harmonious manner, allowing reciprocal advantages for the species involved. This association is permanent, causing dependence indispensable to the survival of the parties, and can no longer detach from each other, due to the collaboration that each exerts on the metabolism of its dependent, probably harmful if they were separated.

Parasitism is an association between two organisms, but it is the type of association that does not promote benefits to both living organisms, on the contrary, in parasitism an organism causes a malfunction in the body of another organism, but its development is favored. For this reason, parasitism cannot be considered a kind of symbiosis.

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Explanation:

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3 years ago

Suppose the half-life is 9.0 s for a first order reaction and the reactant concentration is 0.0741 M 50.7 s after the reaction s

bazaltina [42]

<u>Answer:</u> The time taken by the reaction is 84.5 seconds

<u>Explanation:</u>

The equation used to calculate half life for first order kinetics:

$k=\frac{0.693}{t_{1/2}}$

where,

$t_{1/2}$ = half-life of the reaction = 9.0 s

k = rate constant = ?

Putting values in above equation, we get:

$k=\frac{0.693}{9}=0.077s^{-1}$

Rate law expression for first order kinetics is given by the equation:

$k=\frac{2.303}{t}\log\frac{[A_o]}{[A]}$ ......(1)

where,

k = rate constant = $0.077s^{-1}$

t = time taken for decay process = 50.7 sec

$[A_o]$ = initial amount of the reactant = ?

[A] = amount left after decay process = 0.0741 M

Putting values in equation 1, we get:

$0.077=\frac{2.303}{50.7}\log\frac{[A_o]}{0.0741}$

$[A_o]=3.67M$

Now, calculating the time taken by using equation 1:

$[A]=0.0055M$

$k=0.077s^{-1}$

$[A_o]=3.67M$

Putting values in equation 1, we get:

$0.077=\frac{2.303}{t}\log\frac{3.67}{0.0055}\\\\t=84.5s$

Hence, the time taken by the reaction is 84.5 seconds

6 0

3 years ago

Help in my exam plzz now

swat32

Answer:

yes your answer is correct

I hope it helps mate

I will always help you understanding your assingments have a great day

#Captainpower:)

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Explanation:

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