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Mariana [72]
2 years ago
13

You collect a random sample of size n from a population and calculate a 95% confidence

Mathematics
1 answer:
Vsevolod [243]2 years ago
4 0

A strategy which would produce a new confidence interval with an <u>increased</u> margin of error is to: A. use a 98% confidence level.

<h3>What is a confidence interval?</h3>

A confidence interval simply refers to a range of estimated values which defines the probability that a population parameter will lie within it.

<h3>How to calculate the margin of error?</h3>

Mathematically, a margin of error is calculated by using this formula:

MOE_{\gamma}=Z_{\gamma} \times \sqrt{\frac{\sigma^2}{n} }

From the above formula, we can deduce that the margin of error is directly proportional to the critical value and inversely proportional to the square root of sample size.

This ultimately implies that, increasing the confidence level from 95% to 98% would <u>increase</u> the critical value and by extension the margin of error and vice-versa.

Read more on confidence interval here: brainly.com/question/25779324

#SPJ1

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2and19/90

Step-by-step explanation:

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Find the 7th term of the arithmetic sequence 4x + 5, 11x + 9,18x + 13, ...
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we see the common difference is

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Week 5:14+3=17

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Hope this answers your question :)

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