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2 years ago

6

2(7m−5)+(−8+9m)=?

1 answer:

Anna [14]2 years ago

8 0

Answer:

23m-18

Step-by-step explanation:

2(7m−5)+(−8+9m)

Remove parenthesis

2(7m-5)-8+9m

expand

14m-10

14m-10-8+9

simplify

23m-18

Ask me for more questions brainliest please.

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a cirlcular patio has a diameter of 26ft. inside it is a round flower garden with a diameter of 6ft. to edge the patio and the g

Luden [163]

Answer: C just took the test

Step-by-step explanation:

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2 years ago

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Value of x 9(2x-1)-9x - 18

bixtya [17]

Let's simplify step-by-step.<span><span><span>9<span>(<span><span>2x</span>−1</span>)</span></span>−<span>9x</span></span>−<span>18

</span></span>Distribute:<span>=<span><span><span><span><span><span><span>(9)</span><span>(<span>2x</span>)</span></span>+<span><span>(9)</span><span>(<span>−1</span>)</span></span></span>+</span>−<span>9x</span></span>+</span>−18</span></span><span>=<span><span><span><span><span><span><span>18x</span>+</span>−9</span>+</span>−<span>9x</span></span>+</span>−<span>18

</span></span></span>Combine Like Terms:<span>=<span><span><span><span>18x</span>+<span>−9</span></span>+<span>−<span>9x</span></span></span>+<span>−18</span></span></span><span>=<span><span>(<span><span>18x</span>+<span>−<span>9x</span></span></span>)</span>+<span>(<span><span>−9</span>+<span>−18</span></span>)</span></span></span><span>=<span><span>9x</span>+<span>−<span>27

</span></span></span></span>Answer:<span>=<span><span>9x</span>−<span>27</span></span></span>

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3 years ago

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A certain substance has a half-life of 4 minutes. A fresh sample of the substance weighing 90 mg was obtained. After how many mi

sveticcg [70]

We are to find the time (number of minutes) is would take for 23 mg of the substance to be remaining.

The formula for time is written as:

t = [t1/2 x In(Nt/No)] / In 2

where:

t1/2 = Half life = 4 minutes

No = Initial quantity of the sample = 90 mg

Nt = Amount of the sample left = 23 mg

t = time elapsed = ?

Hence,

t = [4 x In (23/90)] / -In 2

t = 7.8731645610906 minutes

Approximately to the nearest hundredth = 7.87 minutes

Therefore, there will be 23mg of substance remaining after 7.87 minutes.

To learn more, visit the link below:

brainly.com/question/16624562

7 0

2 years ago

Consider the function below. g(x) = 4x − 1 Find the difference quotient below (where h ≠ 0) and simplify your answer. g(x + h) −

eimsori [14]

Answer:

The difference quotient is 4.

Step-by-step explanation:

Given that:

$g(x) = 4x - 1$

To find:

Difference quotient = ?

where $h \neq 0$

Solution:

Formula for Difference quotient is given as:

$\dfrac{g(x+h)-g(x)}{h}$

First of all, let us find out $g(x+h)$

Replacing $x$ with $x+h$

$g(x+h) = 4(x+h)-1 \\\Rightarrow g(x+h) = 4x+4h-1$

Now,

$g(x+h)-g(x) = (4x+4h-1 )-(4x-1)\\\Rightarrow g(x+h)-g(x) = 4x+4h-1 -4x+1\\\Rightarrow g(x+h)-g(x) = 4h$

Putting the above value in:

$\dfrac{g(x+h)-g(x)}{h} = \dfrac{4h}{h}$

We are given that, $h \neq 0$

$\therefore \dfrac{4h}{h} = 4$

So, the difference quotient is 4.

3 0

2 years ago

The line l is tangent to the circle with equation x^2 + y^2=10 at the point P.

babunello [35]

Given:

The equation of a circle is

$x^2+y^2=10$

A tangent line l to the circle touches the circle at point P(1,3).

To find:

The equation of the line l.

Solution:

Slope formula: If a line passes through two points, then the slope of the line is

$m=\dfrac{y_2-y_1}{x_2-x_1}$

Endpoints of the radius are O(0,0) and P(1,3). So, the slope of radius is

$m_1=\dfrac{3-0}{1-0}$

$m_1=\dfrac{3}{1}$

$m=3$

We know that the radius of a circle is always perpendicular to the tangent at the point of tangency.

Product of slopes of two perpendicular lines is always -1.

Let the slope of tangent line l is m. Then, the product of slopes of line l and radius is -1.

$m\times m_1=-1$

$m\times 3=-1$

$m=-\dfrac{1}{3}$

The slope of line l is $-\dfrac{1}{3}$ and it passs through the point P(1,3). So, the equation of line l is

$y-y_1=m(x-x_1)$

$y-3=-\dfrac{1}{3}(x-1)$

$y-3=-\dfrac{1}{3}(x)+\dfrac{1}{3}$

Adding 3 on both sides, we get

$y=-\dfrac{1}{3}x+\dfrac{1}{3}+3$

$y=-\dfrac{1}{3}x+\dfrac{1+9}{3}$

$y=-\dfrac{1}{3}x+\dfrac{10}{3}$

Therefore, the equation of line l is $y=-\dfrac{1}{3}x+\dfrac{10}{3}$ .

4 0

2 years ago