12 ÷ 3 - 5(12) + 4(12 - 2)
= 4 - 60 + 4(10)
= -56 +40
= -16
Answer:
C) 0 ≤ x ≤ 25
Step-by-step explanation:
We are supposed to find a reasonable constraint so that the function is at least 300 i.e. the value of x at which f(x) is greater or equal to 300
A)x ≥ 0
Refer the graph
At x = 0
f(x)=300
On increasing the value of x , f(x) increases but at x = 12 it starts decreasing
So, x ≥ 0 can also have f(x)<300
So, Option A is wrong
B)−5 ≤ x ≤ 30
At x = -5
f(x) = 100
So, Option B is wrong since we require f(x) is greater or equal to 300
c)0 ≤ x ≤ 25
At x = 0
f(x)=300
At x = 12 , it starts decreasing
At x = 25
f(x)=300
So, The value of f(x) is at least 300 when 0 ≤ x ≤ 25
D)All real numbers
At x = 30
f(x)=0
But we require f(x) greater or equal to 300
Hence Option C is true
Ali saves Rs 2576 every month
Step-by-step explanation:
- Step 1: Given Ali's monthly salary = Rs 18400. Calculate the amount spent on food articles
Amount spent on food = 30% of 18400 = 30/100 × 18400 = Rs 5520
- Step 2: Find the remaining amount.
Remaining amount = 18400 - 5520 = Rs 12880
- Step 3: Find amount spend on conveyance and clothes
Amount spent on conveyance and clothes = 40% of 12880
= 40/100 × 12880 = Rs 5152
- Step 4: Find his monthly savings.
Monthly savings = 50% of 5152 = 50/100 × 5152 = Rs 2576
Answer:
For the first 30 minutes, we will have a line with a given steepness, this will represent the 30 minutes riding at a fast pace.
Then he stops for 20 minutes, we will represent this with a constant line.
Then he again moves for another 30 minutes, but with a slower pace than in the first 30 minutes, then this line will be less steep than the first line.
A sketch of this situation can be seen below.
