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3 years ago

Can someone help me pleaseeee

Mathematics

2 answers:

Galina-37 [17]3 years ago

8 0

Yes! The answer is C.

Kruka [31]3 years ago

7 0

I believe the answer is c

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What is an equation of the line that passes through the points (4,3) and (-6,3)?

Shalnov [3]

Answer:

y = 0x +3 or just y = 3

Step-by-step explanation:

m= 3-3/-6-4

= 0/-10 = 0

3= 0(4) +b

3=b

7 0

3 years ago

use the circle graph show below to answer the question a pie chart labeled favorite sports to watch is divided into into three p

mart [117]

From the pie chart described, the percent of people that responded that football was their favorite sport to watch is 42% which represents 210 of the people surveyed.

Let the number of people surveyed be x, then

$42%\ of\ x=210 \\ \\ \Rightarrow0.42x=210 \\ \\ \Rightarrow x= \frac{210}{0.42} =500$

Therefore, the number of people surveyed is 500 people.

6 0

3 years ago

10 POINTSSSSSS HALPPP

dezoksy [38]

Answer:

51.9

8.9

78.5

8.8

Explanation:

You round up if the number to the right is 5 or greater.

So, apply this to the numbers and the 8 in A rounds up, going to a 51.9.

The 9 does not round up because of the one.

The 5 also does not round up because of the 2.

The 7 does round up because of the 6.

8 0

3 years ago

Can someone help me with factoring by grouping

Wittaler [7]

Factor : x^2+3x-10

Answer = (x - 2)(x + 5)

Explanation:

Y = x^2 + 3x - 10.

Find 2 numbers knowing sum (3) and product (-10).

Factor pairs of (-10) -> (-1, 10)(-2, 5). This sum is 3 = b. The 2 numbers are: -2 and 5.

y = (x - 2)(x + 5).

6 0

3 years ago

Read 2 more answers

part 2. Find the value of the trig function indicated, use for that Pythagorean theorem to find the third side if you need it.

andreev551 [17]

Answer: $\bold{5)\ \cos \theta=\dfrac{\sqrt{11}}{6}\qquad 6)\ \tan \theta =\dfrac{8}{17}\qquad 7)\ \cos \theta = \dfrac{4}{3}\qquad 8)\ \cos \theta = \dfrac{\sqrt{10}}{10}}$

<u>Step-by-Step Explanation:</u>

Pythagorean Theorem is: a² + b² = c² , <em>where "c" is the hypotenuse</em>

$5)\ \cos \theta=\dfrac{\text{side adjacent to}\ \theta}{\text{hypotenuse of triangle}}=\dfrac{3\sqrt{11}}{18}\quad \rightarrow \large\boxed{\dfrac{\sqrt{11}}{6}}$

Note: (15)² + (3√11)² = hypotenuse² → hypotenuse = 18

$6)\ \cos \theta=\dfrac{\text{side adjacent to}\ \theta}{\text{hypotenuse of triangle}}=\dfrac{8}{17}\quad =\large\boxed{\dfrac{8}{17}}$

Note: 8² + 15² = hypotenuse² → hypotenuse = 17

$7)\ \tan \theta=\dfrac{\text{side opposite to}\ \theta}{\text{side adjacent to}\ \theta}=\dfrac{20}{15}\quad \rightarrow \large\boxed{\dfrac{4}{3}}$

Note: hypotenuse not needed for tan

$8)\ \cos \theta=\dfrac{\text{side adjacent to}\ \theta}{\text{hypotenuse of triangle}}=\dfrac{2}{2\sqrt{10}}\quad =\large\boxed{\dfrac{\sqrt{10}}{10}}$

Note: 2² + 6² = hypotenuse² → hypotenuse = 2√10

8 0

3 years ago