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3 years ago

12

Last year, the Humane Society of a certain city took in 21,320 animals. If the Humane Society was open all 52 weeks that year, h

ow many animals were taken in each week on average?

2 answers:

ira [324]3 years ago

8 0

They took in 410 animals each week

Gekata [30.6K]3 years ago

7 0

21,320 animals / 52 weeks
= 410 animals per week on average

Hope this helped.

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The total fare for two adults and three children on an excursion boat is $14. If each childs fare is one half of each adults far

zvonat [6]

Make each adult x and each kid 5x
and
set equal to 14.
so it would be
3.5x=14.
14/3.5 = 4
so
x = 4.
adult tickets are 4$ while kids are 2$

7 0

2 years ago

Read 2 more answers

Please solve this question!!

GaryK [48]

Answer: (i) 1/221 (ii) 11/221 (iii) 95/663 (iv) 1/663

<u>Step-by-step explanation:</u>

(i) A deck of cards contains 4 Kings out of 52 total cards

1st draw: 4 Kings out of 52 total cards → 4/52 = 1/13

2nd draw: 3 remaining Kings out of 51 total remaining cards → 3/51 = 1/17

<u>1st Draw </u> <u>2nd Draw </u> <u>Outcome</u> <u>Probability</u>

King: P(K) = 1/13 King: P(K₂/K₁) = 1/17 King, King (1/13) x (1/17) = 1/221

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(ii) A deck of cards contains 4 Jacks, 4 Queens, & 4 Kings out of 52 total cards

1st draw: 12 Face cards out of 52 total cards → 12/52 = 3/13

2nd draw: 11 remaining Face cards out of 51 total remaining cards → 11/51

<u>1st Draw </u> <u>2nd Draw </u> <u>Outcome</u> <u>Probability</u>

Face: P(F) = 3/13 Face: P(F₂/F₁) = 11/51 Face,Face (3/13) x (11/51) = 11/221

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(iiI) A deck of cards contains 26 black cards out of 52 total cards but there are 2 black Jacks, 2 black Queens, and 2 black Kings.

1st draw: 20 Black (not Face) cards out of 52 total cards → 20/52 = 5/13

2nd draw: 19 remaining Black (not Face) cards out of 51 total remaining cards → 19/51

<u>1st Draw </u> <u>2nd Draw </u> <u>Outcome</u> <u>Probability</u>

Black: P(B~) = 5/13 Black: P(B~₂/B~₁) = 19/51 B~,B~ (5/13) x (19/51) = 95/663

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(ii) A deck of cards contains 4 Aces out of 52 total cards

1st draw: 4 Aces out of 52 total cards → 4/52 = 1/13

2nd draw: 1 Queen of Hearts out of 51 total remaining cards → 1/51

<u>1st Draw </u> <u>2nd Draw </u> <u>Outcome</u> <u>Probability</u>

Ace: P(A) = 1/13 Qh: P(Qh₂/A₁) = 1/51 Ace,Queen(h) (1/13) x (1/51) = 1/663

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3 years ago

What's is 17% of 800. ?

stepladder [879]

You need to change 17% to decimal by moving the decimal to the right by 2x so you will get .17*800=136

5 0

3 years ago

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Determine the end behavior of P(x)=3x

ELEN [110]

Answer:

As x ⇒-∞, P(x) ⇒ -∞

As x ⇒ ∞, P(x) ⇒ ∞

Step-by-step explanation:

To find left hand end behavior, plug in negative infinity into the function and evaluate...

P(x) = 3(-∞) = -3(∞) = -∞

The 'y' values of the function decrease towards negative infinity as the 'x' values approach negative infinity

P(x) = 3(∞) = ∞

The 'y' values of the function increase towards positive infinity as the 'x' values approach positive infinity

6 0

3 years ago

Mrs. Lin is sewing costumes for her grandchildren. She is making three lion costumes, one zebra costume, and two bear costumes.

stepladder [879]

Answer:

$12\frac{1}{8}\ yd$

Step-by-step explanation:

we know that

The total fabric that Mrs. Lin needs is equal to

$3(1\frac{2}{3})+2\frac{5}{8}+2(2\frac{1}{4})$

Convert mixed number to an improper fraction

$1\frac{2}{3}=1+\frac{2}{3}=\frac{5}{3}$

$2\frac{5}{8}=2+\frac{5}{8}=\frac{21}{8}$

$2\frac{1}{4}=2+\frac{1}{4}=\frac{9}{4}$

substitute

$3(\frac{5}{3})+\frac{21}{8}+2(\frac{9}{4})$

$5+\frac{21}{8}+\frac{9}{2}$

$\frac{40+21+36}{8}=\frac{97}{8}\ yd$

Convert to mixed number

$\frac{97}{8}\ yd= \frac{96}{8}+\frac{1}{8}=12\frac{1}{8}\ yd$

4 0

3 years ago