Which value is an input of the function? -14 O-2 o ОО 4.

What is the domain of the square root function graphed below

Lina20 [59]

Answer:

Dominio de una Raíz cuadrada

Cuando tenemos una raíz, para estudiar su existencia debemos saber que una raíz existe si y solo sí el radicando (lo que está dentro de la raíz) sea mayor o igual a cero.

Por lo tanto deberemos estudiar el signo de lo que se encuentra dentro de la raíz; y determinar las zonas positivas y las raíces que son las zona de existencia de la función raíz o dominio de esta función.

Step-by-step explanation:

qsy

5 0

3 years ago

A boy who is flying a kite lets out 300 feet of string which makes an angle of 60o with the ground. Assuming that the string is

Aleks [24]

<h3>Answer :</h3>

See the attachment for better understanding.

Given : Length of string (AC) = 300ft

To Find : Height of the kite from ground (AB)

$:\implies\sf\:sin60^{\circ}=\dfrac{AB}{AC}$

$:\implies\sf\:\dfrac{\sqrt{3}}{2}=\dfrac{H}{300}$

$:\implies\sf\:H=\dfrac{300\sqrt{3}}{2}$

$:\implies\sf\:H=150\sqrt{3}$

$:\implies\:\boxed{\bf{\red{H\approx 260\:feet}}}$

Hope it helps !

6 0

3 years ago

Which of the following angles are supplementary to _1? Plsss Help

dolphi86 [110]

Angle 8 because supplementary is two angles whose sum is 180°.

6 0

2 years ago

Read 2 more answers

A theorem is proved using a geometric proof. True or False?

Lerok [7]

A theorem is defined as an existing fact that was proved to be correct through experimentation or mathematical reasoning. In this case, we can say that a theorem can be proven by geometric proof as it is required for people to consider it as a fact. Answer is true.

6 0

3 years ago

A cup of coffee at 93 degrees Celsius is placed in a room at 23 degrees Celsius. Suppose that the coffee cools at a rate of 1 de

Alinara [238K]

Answer:

Step-by-step explanation:

The rate of change of temperature of the coffee with respect to time is expressed by the differential equation

dT/dt=k(T−A) when k = -1 and A = 23. The equation will become:

dT/dt = -(T-23)

If the coffee cools at the rate of 1°C per minute, then dT/dt = -1 and T = 70

Substituting into the equation:

-1 = k(70-23)

-1 = 47k

k = -1/47

k = -0.0213

Substituting k = -0.0213 into the original equation, the differential equation will be:

dT/dt=k(T−A)

dT/dt = -0.0213(T-23)

dT/dt = -0.0213T+0.489

To get the value of T, we will use variable separable method

dt = dT/-0.0213T+0.489

Integrate both sides

t = -0.0213ln(-0.0213T+0.489)

At t = 1 minute

1 = -0.0213ln(-0.0213T+0.489)

1/-0.0213 = ln(-0.0213T+0.489)

-46.95 = ln(-0.0213T+0.489)

Apply exp to both sides

e^-46.95 = e^ln(-0.0213T+0.489)

4.073×10^-21= -0.0213T+0.489

-0.0213T = 4.073×10^-21-0.489

-0.0213T = -0.489

T = 0.489/0.0213

T = 22.96°C

5 0

3 years ago