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2 years ago

Which value is an input of the function? -14 O-2 o ОО 4.

Mathematics

1 answer:

Zarrin [17]2 years ago

4 0

The answer to this problem is D. 4

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Xavier, Yessie, and Zorro each choose a different favorite positive fraction. Each fraction is in simplest form. Yessie's fracti

ad-work [718]

Let Xavier's favourite fraction be a/b, Yessie's favourite fraction = b/a and Zorro's favourite fraction = c/d,

c/d x a/b = 12/35 . . . . . . . . (1)
c/d x b/a = 15/7 . . . . . . . . (2)

(1) x (2) = c/d x a/b x c/d x b/a = 12/35 x 15/7
c^2 / d^2 = 36/49
c^2 = 36
c = 6
d^2 = 49
d = 7

Xaviers favourite fraction = 12/35 / 6/7 = 2/5
Yessies favourite fraction = 5/2
Zorro favourite fraction = 6/7

8 0

2 years ago

What is the final amount if 700 is increased by 4% followed by a further 3% increase?

Archy [21]

Is my Guss is 300 by the fardes I can think of

3 0

2 years ago

Len's recipe for blueberry muffins calls for 110.25 g of brown sugar for the muffin batter and an additional 55.45 g of brown su

nasty-shy [4]

This may be wrong but this is how id do it.

110.25 + 55.45 = 165.7

165.7 x 4.5 = 745.65 g of brown sugar

6 0

3 years ago

Help much needed ✨ Thank you

Radda [10]

1 = 64
2 = 44
3 = 5 over 1

3 0

2 years ago

Read 2 more answers

An object is dropped from a small plane. As the object falls, its distance, d, above the ground after t seconds, is given by the

DedPeter [7]

The inequality can be used to find the interval of time taken by the object to reach the height greater than 300 feet above the ground is:

$d = -16t^2 + 1000$

Solution:

The object falls, its distance, d, above the ground after t seconds, is given by the formula:

$d = -16t^2 + 1000$

To find the time interval in which the object is at a height greater than 300 ft

Frame a inequality,

$-16t^2 + 1000 > 300$

Solve the inequality

Subtract 1000 from both sides

$-16t^2 + 1000 - 1000 > 300 - 1000\\\\-16t^2 > -700$

$16t^2 < 700\\\\Divide\ both\ sides\ by\ 16\\\\t^2 < \frac{700}{16}\\\\Take\ square\ root\ on\ both\ sides\\\\t < \sqrt{\frac{700}{16}}\\\\t < \pm 6.61$

Time cannot be negative

Therefore,

t < 6.61

And the inequality used is: $-16t^2 + 1000>300$

6 0

2 years ago