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LiRa [457]
2 years ago
8

The zoo charges the Garcia family an admission fee of $5 per person

Mathematics
1 answer:
Jet001 [13]2 years ago
6 0

answer :

I could help you if you put the question correctly

You might be interested in
Is 88,490,144 divisible by 9?
Vlad [161]

Answer:

No

Step-by-step explanation:

The sum of the digits is 40 which is not divisible by 9, so it is not divisible by 9

3 0
2 years ago
Read 2 more answers
The supplement of an angle is three times the measure of the angle.
stira [4]

Answer: The angle equals  45 ∘  and the supplement is  135 ∘

Explanation:

Since the supplement is three times the angle, we can say    s  =  3 a

Since we know the supplement is  

180 − a , we can plug that in.

180 - a = 3a

180  = 4 a  (add  a  to both sides)

45  =  a  (divide both sides by  4)

Since we know the angle now, all we have to do is multiply it times  3  to find the supplement.

45  ×  3  =  135

4 0
2 years ago
Given WRST is a parallelogram and
daser333 [38]
It would be a parallelogram 
3 0
3 years ago
3/7 of 8th graders play sports. is 3/5 of the 8th graders that play sports are boys, what fraction of the 8th graders are boys
Svetach [21]

Answer:

\dfrac{9}{35} is the fraction of 8th graders who are boys.

Step-by-step explanation:

Let total number of 8th graders = x

Given that, \frac{3}{7} of 8th graders play sports

\Rightarrow 8th graders who play sports = \frac{3}{7} \times x

Also, Given that, \frac{3}{5} of 8th graders that play sports are boys

Number of 8th graders that play sports, and are boys = \frac{3}{5} \times \text{Number of 8th graders who play sports}

\Rightarrow \dfrac{3}{5} \times \dfrac{3}{7} \times x\\\Rightarrow \dfrac{9}{35} \times x

Hence, the answer is:

\dfrac{9}{35} is the fraction of 8th graders who are boys.

6 0
2 years ago
Find an equation of the plane consisting of all points that are equidistant from (-3, 5, -4) and (-5, 0, 4), and having -2 as th
Firdavs [7]

Answer:

-2x-5y+8z+4.5=0

Step-by-step explanation:

Let (x,y,z) be the coordinates of the point lying on the needed plane. This point is equidistant from the points (-3, 5, -4) and (-5, 0, 4), so

d_1=\sqrt{(x-(-3))^2+(y-5)^2+(z-(-4))^2}=\sqrt{(x+3)^2+(y-5)^2+(z+4)^2}\\ \\d_2=\sqrt{(x-(-5))^2+(y-0)^2+(z-4)^2}=\sqrt{(x+5)^2+y^2+(z-4)^2}\\ \\d_1=d_2\Rightarrow \sqrt{(x+3)^2+(y-5)^2+(z+4)^2}=\sqrt{(x+5)^2+y^2+(z-4)^2}\\ \\(x+3)^2+(y-5)^2+(z+4)^2=(x+5)^2+y^2+(z-4)^2\\ \\x^2+6x+9+y^2-10y+25+z^2+8z+16=x^2+10x+25+y^2+z^2-8z+16\\ \\-4x-10y+16z+9=0\\ \\-2x-5y+8z+4.5=0

5 0
3 years ago
Read 2 more answers
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